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vampirchik [111]
3 years ago
13

What is the answer to K/2+1-1k=-2k

Mathematics
1 answer:
Mazyrski [523]3 years ago
4 0

\dfrac{k}{2}+1-1k=-2k\\\\\dfrac{1}{2}k+1-k=-2k\\\\\left(\dfrac{1}{2}k-k\right)+1=-2k\\\\-\dfrac{1}{2}k+1=-2k\qquad\text{subtract 1 from both sides}\\\\-\dfrac{1}{2}k=-2k-1\qquad\text{add 2k to both sides}\\\\1\dfrac{1}{2}k=-1\qquad\text{convert the mixed number to improper fraction}\\\\\dfrac{1\cdot2+1}{2}k=-1\\\\\dfrac{3}{2}k=-1\qqua\text{multiply both sides by}\ \dfrac{2}{3}\\\\\boxed{k=-\dfrac{2}{3}}

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I need help with this prom now please and thank youl
sattari [20]

Answer:

cannot

not constant

Step-by-step explanation:

1st rate of change is 5 - (-1) / 4 - 2 = 6 / 2 = 3

2nd rate of change is  15 - 5  / 6 - 4 = 10 / 2 = 5

3rd rate is 29 - 15 / 8 - 6 = 14 / 2 = 7

cannot be modeled into a linear equation

rate of change is not constant

7 0
3 years ago
(( REPOST ))((THIS IS MULTIPLE CHOICE BUT I NEED HELP ))
bekas [8.4K]

Answer:

117417 people

Step-by-step explanation:

Let's use the equation A = Pe^rt.

A = amount

P = starting amount

r = rate

t = time

Let's find r first using years 2002 and 2003.

35200 = 32000e^r

Divide each side by 32000.

35200/32000 = e^r

Take the ln() of each side.

r = ln(35200/32000)

Now we can solve for year 2015.

A = 32000e^ln(35200/32000)*13

A = 32000e^1.2390323374562242

A = 110473

5 0
4 years ago
Read 2 more answers
each class AT BRIARWOOD ELEMentary collected at least 54 cans during the food drive. If there were 29 classes in the school what
sertanlavr [38]
You multiply 54 by 29 which will leave you with 1566
6 0
3 years ago
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Currency on hand = 100,000 Brazilian cruzeiros
Vladimir79 [104]

Answer: $18,552.9

Step-by-step explanation:

given data:

currency on hand = $100,000 Brazilian dollar.

curreach desired = us dollars.

if $1 USD = $5.39 Brazilian dollar.

therefore;

$100,000 Brazilia USD

= $100,000/5.39

= $18552.9 USD.

The desired amount in US dollars is $18,552.9

4 0
3 years ago
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SOMEONE PLS HELP ASAP!!!
ladessa [460]

Answer: h(x)=10(0.4)^x

Step-by-step explanation:

The exponential function h, represented in the table, can be written as h(x)=ab^x

From table, at x=0, h(x) =10

Put theses values in equation,, we get

10=a.b^0\\\\\Rightarrow\ 10=  a (1)\\\\\Rightarrow\ a= 10

Also, for x= 1 , h(x) = 4, so put these values and a=10 in the equation , we get

4=10b^1\\\\\Rightarrow\ b=\dfrac{4}{10}\\\\\Rightarrow\ b= 0.4

Put value of a and b in the equation ,

h(x)=10(0.4)^x  →  Required equation.

5 0
3 years ago
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