-(7+8/100)
= -(7+4/50)
= -(7+2/25)
= -177/25
A) His estimate is incorrect, since he has increased a figure to the amount that each employee would receive.
B) Rounded to the nearest dollar, each employee would receive $ 209.
Since a company has $ 6582 to give out in bonuses, and an amount is to be given out equally to each of the 32 employees, and A) a manager, Jake reasoned that since 32 goes into 64 twice, each employee will get about $ 2000 , to determine if his estimate is correct, and B) determine how much will each employee receive, rounded to the nearest whole dollar, the following calculations must be performed:
A)
- 2000 x 32 = 64000
- 200 x 32 = 6400
Therefore, his estimate is incorrect, since he has increased a figure to the amount that each employee would receive.
B)
Therefore, rounded to the nearest dollar, each employee would receive $ 209.
Learn more about maths in brainly.com/question/8865479
9514 1404 393
Answer:
C, D, E
Step-by-step explanation:
Collect terms. The last three options are all equivalent to ...
5.9a - 5.6b
Ist amount paid = $1500
Making $350 for 10 months = 10*350 = $3500
Total amount paid = 1500 + 3500 = 5000
So an amount of $5000 was paid to cover the cost of $4500 within the ten month period.
I = PRT
Interest, I = 5000 - 4500 = 500Time, t = 10 months = 10/12 = (5/6) year.Principal P = 4500
R = I /(PT) R = 500 / (4500*5/6)
R = (500*6) / (4500*5)
R = 0.1333..
R ≈ 13.33 % per annum.
Lan is 146 centimeters tall now.
<u><em>Explanation</em></u>
Let, Lan's current height is
centimeters
As Lisa is 6 centimeters taller than Lan and Lan is 10 centimeters taller than Jim, so Lisa's current height =
centimeters and Jim's current height =
centimeters.
Every month, their heights increase by 2 centimeters.
So, after 5 months.....
Lan's height =
centimeters,
Lisa's height =
centimeters and
Jim's height =
centimeters
Given that, the sum of Ian's and Jim's heights will be 140 centimeters more than Lisa's height in 5 months. So the equation will be....

So, the current height of Lan is 146 centimeters.