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2 years ago

7

Which molecule will undergo only london dispersion forces when interacting with other molecules of the same kind?

1 answer:

vfiekz [6]2 years ago

7 0

Explanation:

London dispersion forces will form between non-polar molecules(polar ) that are symmetrical like O₂, H₂, Cl₂ and noble gases.

The attraction here is because non-polar molecules becomes polar due to the constant motion of its electrons.
This lead to an uneven charge distribution at an instant.
A temporary dipole or instantaneous dipole forms.
The temporary dipole can induce neighboring molecules to be distorted and forms dipoles as well.
This forms london dispersion forces.

Learn more:

Intermolecular forces brainly.com/question/10602513

#learnwithBrainly

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When a force is acting at axis of rotation,why torque is zero?

Vikki [24]

Explanation:

see, torque=force × perpendicular distance

...that perpendicular distance is between axis of rotation and the point where force acts... so in above's case perpendicular distance is zero... so the torque is zero!

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2 years ago

A solid disk of radius 1.4 cm and mass 430 g is attached by a wire to one of its circular faces. It is twisted through an angle

Neporo4naja [7]

Answer:

f= 4,186 10² Hz

Explanation:

El sistema descrito es un pendulo de torsión que oscila con con velocidad angular, que esta dada por

w = √ k/I

donde ka es constante de torsion de hilo e I es el momento de inercia del disco

El momento de inercia de indican que giran un eje que pasa por enronqueces

I= ½ M R2

reduzcamos las cantidades al sistema SI

R= 1,4 cm = 0,014 m

M= 430 g = 0,430 kg

substituimos

w= √ (2 k/M R2)

calculemos

w = RA ( 2 370 / (0,430 0,014 2)

w = 2,963 103 rad/s

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3 years ago

Water enters a baseboard radiator at 180 °F and at a flow rate of 2.0 gpm. Assuming the radiator releases heat into the room at

beks73 [17]

Answer:

Temperature of water leaving the radiator = 160°F

Explanation:

Heat released = (ṁcΔT)

Heat released = 20000 btu/hr = 5861.42 W

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Volumetric flowrate = 2 gallons/min = 0.000126 m³/s; density of water = 1000 kg/m³

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H = ṁcΔT = 5861.42

ΔT = 5861.42/(0.126 × 4200) = 11.08 K = 11.08°C

And in change in temperature terms,

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11.08°C = 11.08 × 18/10 = 20°F

ΔT = T₁ - T₂

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3 years ago

A uniform ladder 5.0 m long rests against a frictionless, vertical wall with its lower end 3.0 m from the wall. The ladder weigh

DiKsa [7]

Answer:(a)360N,(b)171N,(c)2.702m

Explanation:

(a)Maximum Friction Force = $\mu \left ( N\right )=0.4\times \left ( 740+160\right )$

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$sin\theta =\frac{4}{5}$

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(c)

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VikaD [51]

Answer:

https://young.scot/get-informed/national/gender-identity-terms

Explanation:

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