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Tema [17]
3 years ago
9

A child uses a rubber band to launch a bottle cap at an angle of 37.0° above the horizontal. The cap travels a horizontal distan

ce of 1.30 m in 1.20 s. What was the initial speed of the bottle cap, just after leaving the rubber band, in m/s
Physics
1 answer:
zavuch27 [327]3 years ago
3 0

Answer:

Initial velocity will be 1.356 m/sec      

Explanation:

Let the initial speed = u

Angle at which rubber band is launched = 37°

Horizontal component of initial velocity u_x=ucos\Theta =ucos37^{\circ}=0.7986u

Time is given as t = 1.20 sec

Distance in horizontal direction = 1.30 m

We know that distance = speed × time

So time t=\frac{distance}{speed}

1.20=\frac{1.3}{0.7986u}

u=1.356m/sec

So initial velocity will be 1.356 m/sec

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