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3 years ago

Find the value of the expression. (6.885−0.365)÷2+1.44.

Mathematics

2 answers:

olganol [36]3 years ago

7 0

Answer:4.7

Step-by-step explanation:

(6.885-0.365) ➗ 2+1.44

6.52 ➗ 2+1.44

3.26+1.44=4.7

EleoNora [17]3 years ago

4 0

Answer:

4.7

Step-by-step explanation: I bet your family tree is a cactus because everyone on it is a pain/your like the first slice of bread everyone touches you but nobody wants you

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Find the volume if the cylinder. Round your answer to the nearest tenth.

german

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12.6 ft³

Step-by-step explanation:

h = 1 ft

r = 2 ft

π = 3.14

V of cylinder = πr²h

= 3.14 × 2² × 1

= 12.56

= 12.6 ft³

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2 years ago

Help please give the RIGHT answer :( Brainliest too, this is IXL

natta225 [31]

The answer is 3/10 ( hope this helps)

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3 years ago

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Find the equation of the line with slope -2 which goes through the point (-6,-9).

Elena L [17]

(y+3) = −6(x+9) Or y = −6x−57

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3 years ago

PLEASE HELP ME! I AM SO CONFUSED

NemiM [27]

Answer:

b) 13.5

Step-by-step explanation:

Use the trapezoid formula - area.

A = a+b /2 h

=> 4+5/2 · 3 = 13.5

hope this helps and is right :)

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3 years ago

Read 2 more answers

Arrange these functions from the greatest to the least value based on the average rate of change in the specified interval.Tiles

Ugo [173]

By definition, the average rate of change is given by:

$AVR = \frac{f(x2)-f(x1)}{x2-x1}$

We evaluate each of the functions in the given interval.

We have then:

For f (x) = x ^ 2 + 3x:

Evaluating for x = -2:

$f (-2) = (-2) ^ 2 + 3 (-2)\\f (-2) = 4 - 6\\f (-2) = - 2$

Evaluating for x = 3:

$f (3) = (3) ^ 2 + 3 (3)\\f (3) = 9 + 9\\f (3) = 18$

Then, the AVR is:

$AVR = \frac{18-(-2)}{3-(-2)}$

$AVR = \frac{18+2}{3+2}$

$AVR = \frac{20}{5}$

$AVR = 4$

For f (x) = 3x - 8:

Evaluating for x =4:

$f (4) = 3 (4) - 8\\f (4) = 12 - 8\\f (4) = 4$

Evaluating for x = 5:

$f (5) = 3 (5) - 8\\f (5) = 15 - 8\\f (5) = 7$

Then, the AVR is:

$AVR = \frac{7-4}{5-4}$

$AVR = \frac{3}{1}$

$AVR = 3$

For f (x) = x ^ 2 - 2x:

Evaluating for x = -3:

$f (-3) = (-3) ^ 2 - 2 (-3)\\f (-3) = 9 + 6\\f (-3) = 15$

Evaluating for x = 4:

$f (4) = (4) ^ 2 - 2 (4)\\f (4) = 16 - 8\\f (4) = 8$

Then, the AVR is:

$AVR = \frac{8-15}{4-(-3)}$

$AVR = \frac{-7}{4+3}$

$AVR = \frac{-7}{7}$

$AVR = -1$

For f (x) = x ^ 2 - 5:

Evaluating for x = -1:

$f (-1) = (-1) ^ 2 - 5\\f (-1) = 1 - 5\\f (-1) = - 4$

Evaluating for x = 1:

$f (1) = (1) ^ 2 - 5\\f (1) = 1 - 5\\f (1) = - 4$

Then, the AVR is:

$AVR = \frac{-4-(-4)}{1-(-1)}$

$AVR = \frac{-4+4}{1+1}$

$AVR = \frac{0}{2}$

$AVR = 0$

Answer:

from the greatest to the least value based on the average rate of change in the specified interval:

f(x) = x^2 + 3x interval: [-2, 3]

f(x) = 3x - 8 interval: [4, 5]

f(x) = x^2 - 5 interval: [-1, 1]

f(x) = x^2 - 2x interval: [-3, 4]

4 0

3 years ago