Answer:
S varies partly directly as M and Q.
S=C.
S=KMQ+C.
For the first one...
speed=80,m=220,Q=30.
80=K20×30+C.
80=600K+C......(I).equation one.
For the second one....
speed=60,m=300,Q=40.
60=K300×40+C.
60=12000K+C.....(ii). equation two.
Minus eqtn(I) from eqtn(ii).
80=600K+C.
- 60=12000K+C.
K=0.01754~0.018.
Substitute K=0.018 into eqtn(I).
80=600K+C
80=600×0.018+C.
80=10.8+C.
C=80-10.8=69.2.
The relation is S=0.018MQ+69.2
when speed is 100 and mass is 250 find the volume.
100=0.018×250×Q+69.2.
100=4.5Q+69.2.
4.5Q=100-69.2
4.5Q=30.8.
Q=30.8/4.5.
Q=6.8~7litres.
Answer:
GFD and jik...a pair of angles on the outer side
<h3>Answers:</h3>
Problem 1
- Domain =
, interval notation (-3, 3] - Range =
, interval notation [-3, 3) - Is it a function? Yes
Problem 2
- Domain =
, interval notation 
- Range = All real numbers, interval notation
- Is it a function? No
Problem 3
- Domain =
, interval notation [-4, 3) - Range =
, interval notation (-4, 3] - Is it a function? Yes
Problem 4
- Domain = All real numbers, interval notation
- Range =
, interval notation ![(-\infty, 4]](https://tex.z-dn.net/?f=%28-%5Cinfty%2C%204%5D)
- Is it a function? Yes
==================================================
Explanations:
- The left most point is when x = -3, and we are not including this value due to the open hole. The other endpoint is included because it is a filled in circle. The domain is therefore which in interval notation is (-3, 3]. We have the curved parenthesis meaning "exclude endpoint" and the square bracket says "include endpoint". The range is a similar story but we're looking at the smallest and largest y values. Though be careful about which endpoint is open/closed. We have a function because it passes the vertical line test.
- The smallest x value is x = -2. There is no largest x value because the arrows say to go on forever to the right. We can say the domain is which in interval notation is . The range is to indicate "all real numbers". This graph fails the vertical line test, so it is not a function. The vertical line test is where we check to see if we can pass a vertical line through more than one point on the curve. In this case, such a thing is possible which is why it fails the test.
- This is the same idea as problem 1, though note the endpoints are flipped in terms of which has an open circle and which doesn't. It is not possible to draw a single vertical line to have it pass through more than one point on the curve, so it passes the vertical line test and we have a function.
- This is a function because it passes the vertical line test. The domain is the set of all real numbers due to the arrows in both directions. Any x value is a possible input. The range is which is the same as saying in interval notation. This is because y = 4 is the largest y value possible. There is no smallest y value due to the arrows.
Step-by-step explanation:
The bike cost $199 to get $199 you do a number line then label 520 then at the end label 321 so then you do -20 then -100 then -50 then -20 then -9. so now you add them up 20+100+50+20+9 which equals =199
so bike cost $199
then 520%×199= 1034.8
or 520%×321=1669.2
so the percentage is 1669.2 or 1034.8 probably 1669.2 but they bot count.
