PLSSSSS HELP MARKING BRAINLIST PLS I THINK NO ONE WILL HELP ME :(

I will give brainliest 35 points The following graph represents the correlation between shoe size and height for 70 people.

Svetllana [295]

Answer:

Positive

Step-by-step explanation:

As height is increasing, shoe size is also increasing (positive slope)

Negative correlation is when one variable increases and the other decreases (negative slope)

5 0

3 years ago

Read 2 more answers

Completely factor and simplify the expression 3x - 9y

mr Goodwill [35]

Your answer is 3(x-3y)

3 0

3 years ago

Give the domain, range, intercepts, asymptotes, intervals of increasing and decreasing, intervals of positive and negative, symm

klemol [59]

$y = \frac{3}{x^{2} - 4} + 1$

Domain: x² - 4 ≠ 0
+ 4 + 4
x² ≠ 4
√x² ≠ √4
x ≠ ±2
x ≠ -2 and x ≠ 2
(-∞, -2) ∨ (-2, 2) ∨ (2, ∞)

Range: y ≠ 1
(-∞, 1) ∨ (1, ∞)

Intervals: Increasing: (0.25 , ∞)
Decreasing: (-∞, 0.25)

Symmetry: X-axis: Not Symmetric
Y-axis: Not Symmetric
Origin: Not Symmteric

Extrema: Maximum Relative: x = 0
Minimum Relative: Nothing

3 0

3 years ago

The diameter of a circle measures 22 yd. What is the circumference of the circle?

luda_lava [24]

Answer:

69.08 yd

Step-by-step explanation:

7 0

3 years ago

Dylan Rieder is a statistics student investigating whether athletes have better balance than non-athletes for a thesis project.

Kobotan [32]

Answer:

$t=\frac{(3.7-4.1)-0}{\sqrt{\frac{1.1^2}{32}+\frac{1.3^2}{45}}}}=-1.457$

$p_v =P(t_{75}$

Comparing the p value with a significance level for example $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can't say that the population mean for the athletes is significantly lower than the population mean for non athletes.

Step-by-step explanation:

Data given and notation

$\bar X_{A}=3.7$ represent the mean for athletes

$\bar X_{NA}=4.1$ represent the mean for non athletes

$s_{A}=1.1$ represent the sample standard deviation for athletes

$s_{NA}=1.3$ represent the sample standard deviation for non athletes

$n_{A}=32$ sample size for the group 2

$n_{NA}=45$ sample size for the group 2

$\alpha=0.01$ Significance level provided

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the population mean for athletes is lower than the population mean for non athletes, the system of hypothesis would be:

Null hypothesis: $\mu_{A}-\mu_{NA}\geq 0$

Alternative hypothesis: $\mu_{A} - \mu_{NA}< 0$

We don't have the population standard deviation's, we can apply a t test to compare means, and the statistic is given by:

$t=\frac{(\bar X_{A}-\bar X_{NA})-\Delta}{\sqrt{\frac{s^2_{A}}{n_{A}}+\frac{s^2_{NA}}{n_{NA}}}}$ (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:

$t=\frac{(3.7-4.1)-0}{\sqrt{\frac{1.1^2}{32}+\frac{1.3^2}{45}}}}=-1.457$

P value

We need to find first the degrees of freedom given by:

$df=n_A +n_{NA}-2=32+45-2=75$

Since is a one left tailed test the p value would be:

$p_v =P(t_{75}$

Comparing the p value with a significance level for example $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can't say that the population mean for the athletes is significantly lower than the population mean for non athletes.

5 0

3 years ago