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- Your answer is no solution.
- Because if we transpose 10x to the left hand side with a change in the symbol, then it will become 0.
- 10x - 1 = 10x +4
- or, 10x - 10x = 4 + 5
- or, 0 = 9
- Hence, the equation has <em><u>no solution</u></em>.
Hope you could get an idea from here.
Doubt clarification - use comment section.
Answer:
Step-by-step explanation:
First confirm that x = 1 is one of the zeros.
f(1) = 2(1)^3 - 14(1)^2 + 38(1) - 26
f(1) = 2 - 14 + 38 - 26
f(1) = -12 + 38 = + 26
f(1) = 26 - 26
f(1) = 0
=========================
next perform a long division
x -1 || 2x^3 - 14x^2 + 38x - 26 || 2x^2 - 12x + 26
2x^3 - 2x^2
===========
-12x^2 + 28x
-12x^2 +12x
==========
26x -26
26x - 26
========
0
Now you can factor 2x^2 - 12x + 26
2(x^2 - 6x + 13)
The discriminate of the quadratic is negative. (36 - 4*1*13) = - 16
So you are going to get a complex result.
x = -(-6) +/- sqrt(-16)
=============
2
x = 3 +/- 2i
f(x) = 2*(x - 1)*(x - 3 + 2i)*(x - 3 - 2i)
The zeros are
1
3 +/- 2i
Answer:
When dividing two values with the same base, we simply subtract the first exponent by the second and keep the original base. 3^3-6=3^-3. This equals out to be 1/27.
Step-by-step explanation:
