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Snowcat [4.5K]
2 years ago
8

Y=x^2-4x-3 y=-2x^2-5x+1

Mathematics
1 answer:
Serggg [28]2 years ago
6 0

Hi! This is the solution of your equation!

Download docx
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what is the difference between a vertical compression and a horizontal stretch? just got a question relating to that wrong and I
Lana71 [14]

Answer:

Vertical compression: the squeezing of the graph toward the x-axis

Horizontal stretch:  the squeezing of the graph toward the y-axis

5 0
2 years ago
Haily walked 15 miles in 9 hours. What was her walking rate in miles per hour? Express your answer in simplest form
Pachacha [2.7K]

Answer:

1.67

Step-by-step explanation:

you should do 15 ÷ 9 and you get 1.6666666667 and when you simplify that you get 1.67

6 0
3 years ago
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IVE BEEN TRYING TO GET THIS FIGURED OUT SINCE 1:00AM MY EYES ARE RED IVE GOTTEN 0 SLEEP, AND I JUST NEEEEEED HELLLLPPPPP 10 PTS
Ede4ka [16]
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3 years ago
What is the midpoint of the segment shown below ?
Hoochie [10]
I'm pretty sure it would be d. you have to add the xs and ys and divide each by 2.
7 0
3 years ago
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What are the real and complex solutions of the polynomial equation? x^3-8=0. with imaginary numbers
seraphim [82]

Answer:

Solutions are 2,  -1 +  0.5 sqrt10 i  and -1 - 0.5 sqrt10 i

or 2,  -1 +  1.58 i  and -1 - 1.58i

(where the last 2 are equal to nearest hundredth).


Step-by-step explanation:

The real solution is x = 2:-

x^3 - 8 = 0

x^3 = 8

x = cube root of 8 = 2

Note that a cubic equation must have  a total of 3 roots ( real and complex in this case).  We can find the 2 complex roots by using the following identity:-

a^3 - b^3 = (a - b)(a^2 + ab + b^2).

Here  a = x and b = 2 so we have

(x - 2)(x^2 + 2x + 4) = 0

To find the complex roots we solve x^2 + 2x + 4 = 0:-

Using the quadratic formula x = [-2 +/- sqrt(2^2 - 4*1*4)] / 2

= -1 +/- (sqrt( -10)) / 2

= -1 +  0.5 sqrt10 i  and -1 - 0.5 sqrt10 i

4 0
2 years ago
Read 2 more answers
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