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Ugo [173]
3 years ago
13

Can someone explain this math problem to me so I can show my son how to solve it please ​

Mathematics
1 answer:
Sav [38]3 years ago
3 0

Answer:

ہندوستان ضنداباد you mad

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For 32 = 5X + 2, what is the first step in solving for X?
nikitadnepr [17]

Answer:

-2 from both sides

Step-by-step explanation:

32=5x+2

-2        -2

________

30=5x

__=__

5      5

6=x

4 0
3 years ago
Round each number to the nearest tenth.
AleksandrR [38]
26.73\approx23.7\\
 89.42\approx89.4
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3 years ago
Place 1/5 on the number line below .
Georgia [21]
Right next to the zero van I heht brainleist please

3 0
3 years ago
General solutions of sin(x-90)+cos(x+270)=-1<br> {both 90 and 270 are in degrees}
mixer [17]

Answer:

\left[\begin{array}{l}x=2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{2}+2\pi k,\ k\in Z\end{array}\right.

Step-by-step explanation:

Given:

\sin (x-90^{\circ})+\cos(x+270^{\circ})=-1

First, note that

\sin (x-90^{\circ})=-\cos x\\ \\\cos(x+270^{\circ})=\sin x

So, the equation is

-\cos x+\sin x= -1

Multiply this equation by \frac{\sqrt{2}}{2}:

-\dfrac{\sqrt{2}}{2}\cos x+\dfrac{\sqrt{2}}{2}\sin x= -\dfrac{\sqrt{2}}{2}\\ \\\dfrac{\sqrt{2}}{2}\cos x-\dfrac{\sqrt{2}}{2}\sin x=\dfrac{\sqrt{2}}{2}\\ \\\cos 45^{\circ}\cos x-\sin 45^{\circ}\sin x=\dfrac{\sqrt{2}}{2}\\ \\\cos (x+45^{\circ})=\dfrac{\sqrt{2}}{2}

The general solution is

x+45^{\circ}=\pm \arccos \left(\dfrac{\sqrt{2}}{2}\right)+2\pi k,\ \ k\in Z\\ \\x+\dfrac{\pi }{4}=\pm \dfrac{\pi }{4}+2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{4}\pm \dfrac{\pi }{4}+2\pi k,\ \ k\in Z\\ \\\left[\begin{array}{l}x=2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{2}+2\pi k,\ k\in Z\end{array}\right.

4 0
3 years ago
The sum of one-third of a number and three-fourths of the number exceeds that number by one. Which equation could be used to fin
Marrrta [24]
\frac{n}{3} + \frac{3n}{4} = n+1 &#10;
4n + 9n = n+1
13n = n+1
13n-n = 1
12n = 1

8 0
3 years ago
Read 2 more answers
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