2 movies
4 hours - .5 popcorn -1.75-1.75=0
Easier terms 4 hours minus 30 min is 3 hours and 30 min left each movie is 1 hour and 45 min plus 1 hour 45 min i that's 2 hours and 90 min 90 min are one hour and 30 min. So 2 hours plus one hour and 30 min is the 3 hours and 30 min are we're left
Answer:
1/6
Step-by-step explanation:
ive seen that question b4
Answer:
where x is the cost of one adult ticket and y is the cost of one child ticket.
Step-by-step explanation:
<em>This is an incomplete question since we would need to know the cost of the adult ticket and the cost of the children ticket.</em>
However, let's say that the price is x dollars per adult and y dollars per child.
Now, we need to find out how much one adult and 6 children paid.
Thus, we would have to multiply the cost per adult by the number of adults and the cost per child per number of children and then sum up these two results.
Writing this in an algebraic way we would have:
Thus, 1 adult and 6 children would have paid x + 6y dollars where x is the cost of the adult ticket and y is the cost of the children ticket.
<em>(For example, if an adult ticket is 6 dollars and a child ticket is 4 dollars we would have that they paid 6 + 6(4) = 6 + 24 = 30 dollars)</em>
41 hop this helps have a great day or night
The given data of the problem are 42 combined dvds from Carly and Rob and Carly having 4 more dvds than Rob. Now, the problem wants to find out how many dvds did Rob and Carly owned before combining them. We got a total of 42 dvds at hand, so let's divide it by 2 for Carly and Rob so we have 21 dvds each however, the problem emphasized that Carly had 4 more dvds than Rob. So, 21 dvds added by 4 dvds is the total number of dvds that Carly previously owned meaning Carly owned 25 dvds before while Rob owned only 17 dvds.