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QveST [7]
3 years ago
12

PLEASE HELP!!

Mathematics
1 answer:
aev [14]3 years ago
8 0

Answer:

D. No, because P(A|B)=0.22 and the P(A) = 0.53 are not equal.

Step-by-step explanation:

Given:

Probability of doing yard work is, P(A)=53\%=0.53

Probability of raining, P(B)=68\%=0.68

Probability of doing yard work and it raining is, P(A\cap B)=15\%=0.15

Now, two events A and B are independent if,

P(A|B)=P(A);P(B|A)=P(B)

Conditional probability of event A given that B has occurred is given as:

P(A|B)=\frac{P(A\cap B}{P(B)}\\P(A|B)=\frac{0.15}{0.68}=0.22

So, P(A|B)=0.22\ and\ P(A)=0.53

Since, P(A|B)\ne P(A), A and B are not independent events.

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