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3 years ago

A number multiplied by 4 is -20

2 answers:

7 0

-5 would be the answer. 4 times -5 would equal -20 because 4 times 5 equals 20 and a positive number times a negative number equals a negative number. (opposite signs equal negative, same signs equal positive)

If you liked my answer, make sure to leave this answer a Branliest! (:

Karolina [17]3 years ago

6 0

4x = -20

divide by 4 on both sides (4/4 cancels itself out) (-20 / 4 = -5)

x = -5

4 (-5) = -20

-20 = -20

<u>The answer is -5</u>

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Melbourne is a popular tourist location in Florida. The highest temperature ever recorded there was 109°F. The lowest temperatur

Fynjy0 [20]

The inequality that shows the temperature in Melbourne is 20°F ≤ x ≤ 100°F

<h3>What is an inequality?</h3>

An inequality is an expression that shows the non equal comparison of two or more variables and numbers.

Let x represent the temperature in Melbourne.

The highest temperature ever recorded there was 109°F, hence x ≤ 109°F.

Also, the lowest temperature ever recorded there was 20°F, hence x ≥ 20.

From both statements:

20°F ≤ x ≤ 100°F

The inequality that shows the temperature in Melbourne is 20°F ≤ x ≤ 100°F

Find out more on inequality at: brainly.com/question/24372553

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3 years ago

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Read 2 more answers

A pilot wishes to fly on a course of 290° with an air speed of 300 knots when the wind blows from 224° at 18 knots. Find the dri

dolphi86 [110]

Answer:

Step-by-step explanation:

The resulting course vector (magnitude 300, angle = 160° with the positive x axis (= 290° bearing)) with components (300cos160,300sin160) is the sum of the vector of the actual flight vector and the wind vector.

The wind vector has magnitude 18 and direction 46° with the positive x-axis ( it blows from - 134° with the positive x axis (= 224° bearing) into direction 46° with the positive x-axis). So its components are (18cos46,18sin46).

The course that the plane has to steer is :

(300cos160,300sin160)-(18cos46,18sin46)

=(300cos160 - 18cos46, 300sin160 - 18sin46)

=(-294.41, 89.6579)

The magnitude of this steering vector is = 307.749 knots and its direction will be:

$tan^{-1}=\frac{89.6579}{294.41}=16.94^{{\circ}}$ with the negative x-axis (286.94° bearing).

Thus, the drift angle will be=290° - 286.94° = 3.06°.

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3 years ago