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3 years ago

Add this fraction 6 3/8 4 1/8

1 answer:

8 0

$6\frac{3}{8} + 4\frac{1}{8}$

1. Add the whole numbers

$6 + 4 = 10$

2. Add the fractions

$\frac{3}{8} + \frac{1}{8} = \frac{4}{8}$

$6\frac{3}{8} + 4\frac{1}{8} = 10\frac{4}{8}$

3. Reduce

$10\frac{4 / 4}{8 / 4} = 10\frac{1}{2}$

$6\frac{3}{8} + 4\frac{1}{8} = 10\frac{4}{8} = 10\frac{1}{2}$

The answer is 10 1/2

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3 years ago

there are two boxes. in the first box there are 7 cards numbered from 1 tp 7 the second box also contains 7 cards from 1-7 pick

mrs_skeptik [129]

Answer:

$\frac{6}{49}$

Step-by-step explanation:

GIVEN: There are two boxes. in the first box there are $7$ cards numbered from $1$ to $7$ the second box also contains $7$ cards from $1-7$ pick one card from each box.

TO FIND: probability that the sum of the two two cards is at least $12$ .

SOLUTION:

sample case such that sum of cards is $12$ : $(5,7),(7,5),(6,6)$

sample case such that sum of cards is $13$ : $(7,6),(6,7)$

sample case such that sum of cards is $14$ : $(7,7)$

Total sample case such that sum is atleast $12$ $=6$

Total sample cases $=49$

probability that the sum of the two two cards is at least $12$ $=\frac{\text{sample case in which sum is atleast 12}}{\text{total sample cases}}$

$=\frac{6}{49}$

probability that the sum of the two two cards is at least $12$ is $\frac{6}{49}$

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3 years ago

Arrange the expressions in increasing order of their values.

Arada [10]

Answer:

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Step-by-step explanation:

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So we do tan(30)/1 = 5/b, and cross multiply.

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3 years ago