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lozanna [386]
3 years ago
14

1. A sample consists of 75 TV sets purchased several years ago. The replacement times of those TV sets have a mean of 8.2 years.

Assume σ= 1.1 years. Find the 95% confidence interval.
Mathematics
1 answer:
Greeley [361]3 years ago
3 0

Answer:

8.2+/-0.25

= ( 7.95, 8.45) years

the 95% confidence interval (a,b) = (7.95, 8.45) years

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x+/-zr/√n

Given that;

Mean x = 8.2 years

Standard deviation r = 1.1 years

Number of samples n = 75

Confidence interval = 95%

z value(at 95% confidence) = 1.96

Substituting the values we have;

8.2+/-1.96(1.1/√75)

8.2+/-1.96(0.127017059221)

8.2+/-0.248953436074

8.2+/-0.25

= ( 7.95, 8.45)

Therefore the 95% confidence interval (a,b) = (7.95, 8.45) years

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Answer:

66%

Step-by-step explanation:

There are 3 feet in a yard therefore 2 feet of a yard is 2/3. 2/3 converted to a percentage is 66%

4 0
2 years ago
Thaddeus has plotted several points on a scatter plot to investigate the relationship between two quantitative variables. He wan
Arturiano [62]

Answer:

no he does not

Step-by-step explanation:

6 0
3 years ago
a rectangular parking lot has a lenth that is 6 yard graeter than the width the area of the parking lot is 160 ssquar yardsd. fi
Lubov Fominskaja [6]

Answer:

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>

Let

the breadth =x

the length =6x

  • \sf Area=160yard^2

As we know that in a rectangle

{\boxed{\sf Area=lb}}

  • Substitute the values

{:}\longrightarrow\sf x\times 6x=160

{:}\longrightarrow\sf 6x^2=160

{:}\longrightarrow\sf x^2={\dfrac {160}{6}}

{:}\longrightarrow\sf x^2=26.6

{:}\longrightarrow\sf x=\sqrt {26.6}

{:}\longrightarrow\sf x=5.1yards

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7 0
3 years ago
Susan is trying to decide between two jobs. One job pays $12 per hour for the first 36 hours and $15 per hour for any additional
nasty-shy [4]

Answer:

For the first question (For which job will she earn more if she works 40 hours a week), the answer is the second job.

For the second question (How much more per year will this be if she works 50 weeks per year), the answer is 25$ extra a year.

First i multiplied $12 times 36.

$12 x 36 = $432

Then i multiplied $15 times 4.

$15 x 4 = $60

Now add those together

$432 + $60 = $492

That's how much she would make in a week for the first job, if she worked 40 hours a week.

For the second job, i did the exact same process.

$11.50 x 35 = $402.5

$18 x 5 = $90

$402.5 + $90 = $492.5

She would get 50 more cents a week, if she worked 40 hours a week.

For the second question, i multiplied the first job total by 50, since she is working 50 weeks a year.

$492 x 50 = $24,600

Thats her total of a year, for the first job.

Do this with the second job.

$492.5 x 50 = $24,625

As you can see, she would get $25 more in the second job, than the first job.

I hope this helped!

7 0
3 years ago
За^n(а^n + a^n-1) what is it??
solniwko [45]
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(3a^n*a^n)+(3a^n*a^n)+(3a^n*-1)
4a^2n+4a^2n-3a^n=
8a^2n-3a^n
8 0
4 years ago
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