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3 years ago

За^n(а^n + a^n-1) what is it??

Mathematics

1 answer:

solniwko [45]3 years ago

8 0

Distribute the 3a^n to all the other values then solve...
(3a^n*a^n)+(3a^n*a^n)+(3a^n*-1)
4a^2n+4a^2n-3a^n=
8a^2n-3a^n

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(3,4) and (12,19) find the equation of the line that passes through it

harina [27]

Answer:

The equation of the line will be:

$y=\frac{5}{3}x-1$

Step-by-step explanation:

Given the points

(3, 4)

(12, 9)

Finding the slope between (3, 4) and (12, 9)

$\left(x_1,\:y_1\right)=\left(3,\:4\right),\:\left(x_2,\:y_2\right)=\left(12,\:19\right)$

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$m=\frac{19-4}{12-3}$

$m=\frac{5}{3}$

The equation of the line can be obtained using the point-slope form of the equation of the line

$y-y_1=m\left(x-x_1\right)$

substituting the values m = 5/9 and the point (3, 4)

$y-4=\frac{5}{3}\left(x-3\right)$

$y-4+4=\frac{5}{3}\left(x-3\right)+4$

$y=\frac{5}{3}x-1$

Therefore, the equation of the line will be:

$y=\frac{5}{3}x-1$

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