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4 years ago

За^n(а^n + a^n-1) what is it??

Mathematics

1 answer:

solniwko [45]4 years ago

8 0

Distribute the 3a^n to all the other values then solve...
(3a^n*a^n)+(3a^n*a^n)+(3a^n*-1)
4a^2n+4a^2n-3a^n=
8a^2n-3a^n

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Find the mean of the set of data: 10, 12, 29, 2, 19, 42, 23, 23

Softa [21]

To find mean,
first add all the numbers together:
10 + 12 + 29 + 2 + 19 + 42 + 23 + 23 = 160

Then divide the total by the amount of numbers there are:

In this case, there are 8 numbers.

160/8 = 20

20 is your mean for this set of data

hope this helps

3 0

3 years ago

A clothing store sold 4 times as many sweaters as coats. The difference in the sales was 300. How many of each were sold?

slava [35]

Sweater = 400
coats = 100
difference= 300
in an equation it would be
4x-x=300
so
3x=300
x=100
sweaters= 4x= 400
coats= x= 100

5 0

3 years ago

The diagram represents a wheelchair ramp to a school.

qaws [65]

Answer:

1/5

Step-by-step explanation:

change in height over change in horizontal run. Which is 10 ft/2ft or 1/5

4 0

3 years ago

In an arithmetic sequence, a_17 = -40 and a_28 = -73. Please explain how to use this information to write a recursive formula fo

Vinvika [58]

An arithmetic sequence

$a_1,a_2,a_3,\ldots,a_n,\ldots$

is one in which consecutive terms of the sequence differ by a fixed number, call it d. This means that, given the first term $a_1$ , we can build the sequence by simply adding d :

$a_2=a_1+d$

$a_3=a_2+d$

$a_4=a_3+d$

and so on, the general pattern governed by the recursive rule,

$a_n=a_{n-1}+d$

We can exploit this rule in order to write any term of the sequence in terms of the first one. For example,

$a_3=a_2+d=(a_1+d)+d=a_1+2d$

$a_4=a_3+d=(a_1+2d)+d=a_1+3d$

and so on up to

$a_n=a_1+(n-1)d$

In this case, we're not given the first term right away, but the 17th. But this isn't a problem; we can use the same exploit to get

$a_{18}=a_{17}+d$

$a_{19}=a_{17}+2d$

$a_{20}=a_{17}+3d$

and so on, up to the next term we know,

$a_{28}=a_{17}+11d=-40+11d$

(Notice how the subscript of a on the right and the coefficient of d add up to the subscript of a on the left.)

The 28th term is -73, so we can solve for d :

$-73=-40+11d\implies -33=11d\implies d=-3$

To get the first term of the sequence, we use the rule found above and either of the known values of the sequence. For instance,

$a_{17}=a_1+16d\implies-40=a_1-16\cdot3\implies a_1=8$

Then the recursive rule for this particular sequence is

$\begin{cases}a_1=8\\a_n=a_{n-1}-3&\text{for }n>1\end{cases}$

7 0

3 years ago

*20 points*

ioda

So hmm notice the picture below

simply get the area of the segment, and subtract it from the area of the circle, what's left, is the difference

notice your circle, has a radius "r" of 18

5 0

4 years ago

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