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fredd [130]
3 years ago
9

Jim invested $10,000 at 2% interest compounded annually over 2 years if the total amount in the account after 2 years is $10,404

how much interest did Gina earn​
Mathematics
1 answer:
Leni [432]3 years ago
4 0
They would have earned $404 dollars in interest
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-1.2= y/2.4 -1.7<br> Solve for y
evablogger [386]

{\huge{\boxed{\sf{Question}}

-1.2= y\div2.4 -1.7

Solve for y

{\huge{\boxed{\sf{Answer\:with\:explanation }}}

let's put our equation first

-1.2= y\div2.4 -1.7

Flip the equation

y\div2.4-1.7=-1.2

Now follow the rule of BOMDAS/PEMDAS

{\huge{\boxed{\sf{BOMDAS }}}

  • Brackets
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  • Division
  • Addition
  • Subtraction

{\huge{\boxed{\sf{PEMDAS}}}

  • Parenthesis
  • Exponents
  • Multiplication
  • Division
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_________________________

{\huge{\boxed{\sf{Solve\:the\:equation}}}

_________________________

y\div2.4-1.7=-1.2

{\underline{simplify}}

0.416667y-1.7=-1.2

add 1.7 to both sides

0.416667y=0.5

Divide both sides by 0.416667

y=1.2

{\huge{\boxed{\sf{Answer}}}

y would equal 1.2

4 0
3 years ago
Describe the end behavior of f(x)=10x^4
Reika [66]
<span>I think when you ask me to describe the end behavior of f(x)=10x^4 you mean for me to answer like this 10^4=10,000.</span>
5 0
4 years ago
The lens of a telescope has a diameter of 2 yards.what is the lens radius?
Alexus [3.1K]
The radius of the lens is 1 yard
4 0
3 years ago
Read 2 more answers
I need to know how to simplify these problems.
nalin [4]
You need to factor the radicals into products of radicals, and when factoring you should keep in mind you want to obtain perfect square roots. So √125 = √5*√25 and squareroot 25 has a definite answer of 5, so ∛125=∛5×∛25=5×√5. You want to follow the general pattern of factoring perfect squares to obtain a number outside the radical which can be multiplied by the current coefficient
5 0
3 years ago
When an ANOVA comparing the means of 3 groups indicates that at least one group is different from the others, a common follow-up
lorasvet [3.4K]

Answer:

ii) a Bonferonni-corrected alpha level of 0.0167 to control the type I error rate for the overall inference to 5% .

Step-by-step explanation:

Previous concepts

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".  

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"  

The hypothesis for this case are:

Null hypothesis: \mu_{A}=\mu_{B}=\mu_{C}

Alternative hypothesis: Not all the means are equal \mu_{i}\neq \mu_{j}, i,j=A,B,C

Since we reject the null hypothesis we want to see which method it's the best to determine which group(s) is (are) different is pairwise two-sample t-tests each assessed using.

And on this case the best option is:

ii) a Bonferonni-corrected alpha level of 0.0167 to control the type I error rate for the overall inference to 5% .

The reason is because the Bonferroni correction "compensates for that increase by testing each individual hypothesis at a significance level of \alpha who represent the desired overall alpha level and m is the number of hypotheses". For our case m=3 hypotheses with a desired \alpha = 0.05, then the Bonferroni correction would test each individual hypothesis at 0.05/3=0.0167

One advatange of this method is that "This method not require any assumptions about dependence among the p-values or about how many of the null hypotheses are true" . And is more powerful than the individual paired t tests.

3 0
4 years ago
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