According to the direct inspection, we conclude that the best approximation of the two solutions to the system of <em>quadratic</em> equations are (x₁, y₁) = (- 1, 0) and (x₂, y₂) = (1, 2.5). (Correct choice: C)
<h3>What is the solution of a nonlinear system formed by two quadratic equations?</h3>
Herein we have two parabolae, that is, polynomials of the form a · x² + b · x + c, that pass through each other twice according to the image attached to this question. We need to estimate the location of the points by visual inspection on the <em>Cartesian</em> plane.
According to the direct inspection, we conclude that the best approximation of the two solutions, that is, the point where the two parabolae intercepts each other, to the system of two <em>quadratic</em> equations are (x₁, y₁) = (- 1, 0) and (x₂, y₂) = (1, 2.5). (Correct choice: C)
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Answer:
4 cm
Step-by-step explanation:
You have an equation and a table with the x value given.
Replace x in the formula with the x value in the table and solve for y.
y = x^2 + 1
y = (-3)^2 + 1 = 9+1 = 10
y = (-2)^2 +1 = 4+1 = 5
y = (-1)^2 +1 = 1+1 = 2
y = (0)^2 + 1 = 0+1 = 1
y = (1)^2 +1 = 1+1 = 2
y = (2)^2 +1 = 4+1 = 5
y = (3)^2 +1 = 9+1 = 10
For this case we have that by definition, the volume of a sphere is given by:
Where:
r: It is the radius of the sphere
According to the statement we have to:
So the volume is:
Rounding we have that the volume of the sphere is: 
Answer:
Option B
Hello,
So they don't intersect !!!!!!!!!!!!!!!!!!!!!!!
