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topjm [15]
3 years ago
15

Do any of you guys no this If 18 is 45% of a value, what is that value?

Mathematics
2 answers:
iragen [17]3 years ago
8 0

Answer:C.40

Step-by-step explanation:

Fynjy0 [20]3 years ago
8 0

Answer:

C. 40

Step-by-step explanation:

18/x = 45/100, x is the value we are looking for

18/x = 45/100

1800/x = 45                   multiply both sides by 100

1800 = 45x                    multiply both sides by x

40 = x                             divide both sides by 45

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1) f(x)=(x - 3)(x - 5)
NemiM [27]

Answer:

Step-by-step explanation:

f(x)= (x - 3)(x - 5)

f(x) = x^2 - 5x - 3x + 15

f(x) = x^2 - 8x + 15

Answer is A

7 0
2 years ago
A taxi charges $7.50 plus $0.45 per mile.
poizon [28]
$7.50(2)=$15.00 (She takes the taxi twice, and its $7.50 each time she takes it)
$0.45(16)+$0.45(8)=$10.80 (Each mile is $0.45, she goes 16 miles on the way to work, and only 8 miles on the way home. Since she walks half way and  takes the taxi the other half. Half of 16 is 8)
$15.00+$10.80=$25.80
Alexis pays $25.00 per day for her taxi rides.
6 0
3 years ago
You don’t need to tell me the answer, but could you tell me the formula on how to get the answer ?
steposvetlana [31]

Formula used: cos(x) = \frac{adjacent}{hypotenuse}

Hope this helped!

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3 0
3 years ago
3. 24 +13
Elodia [21]

Answer:

37

Step-by-step explanation:

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5 0
3 years ago
A dog and a cat are 200 meters apart when they see each other. The dog can run at a speed of 30 meter per second, while the cat
LenKa [72]

Answer:

They'll meet after 200 meters , if they simultaneously start running towards each other.

Step-by-step explanation:

Let x =distance travelled by dog and 200-x be the distance travelled by cat. Inorder to meet, the sum of their travelled distances shall be equal to 200 meters as they are far apart by 200 meters.

Dog: Distance =Speed x time: x=30t

Cat: Distance = 200-x

=24t

The sum of their distance travelled shall be 200 meters: 30t+ 24t= 200;54t=200;t=200/54=3.7secs

So they will meet after 3.7 seconds

To check:

Distance travelled by dog :x=30(3.7)

=111.11 meters

Distance travelled by cat: 24t=24(3.7)

=88.89 meters

Therefore since they are travelling towards each other and their distance apart is 200 meters, after 3.7 seconds they will meet because dog travelled 111.11 meters and cat travelled 88.89 meters and they covered already 200 meters as the sum of 111.11+ 88.89

=200 meters

6 0
2 years ago
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