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3 years ago

3.15trillion in scientific notation

Mathematics

1 answer:

Colt1911 [192]3 years ago

6 0

3.15*10^12 would be 3.15 trillion in scientific notation.

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Please solve this 20×10=

Vadim26 [7]

Answer:

20 × 10 = 200

Step-by-step explanation:

Multiply 2 × 1 = 2 and then add the two zeros onto the end to get 200.

3 0

3 years ago

Use the compass and ruler to construct the bisector of the angle given below.

soldier1979 [14.2K]

Okay so I think you go south now give me ma points

8 0

3 years ago

The factorization below is missing two positive integers a and b. 6x^(3)+18x^(2)-240x=6x(x-a)(x+b) Factor the polynomial and the

Dvinal [7]

Answer:

a = 5

Step-by-step explanation:

Hello, please consider the following.

$6x^3+18x^2-240x=6x(x^2+3x-40)\\\\\text{** The sum of the zeroes is -3=-8+5 and the product is -40=-8*5. **}\\\\\text{** So, we can factorise. **}\\\\6x^3+18x^2-240x=6x(x^2+3x-40)=6x(x^2+8x-5x-40)\\\\=6x(x(x+8)-5(x+8))\\\\\large \boxed{=6x(x+8)(x-5)}$

So, a = 5.

Thank you.

7 0

4 years ago

Please help and explain how you got the answer I am also being timed so please answer quickly thank you for your time

valentina_108 [34]

Answer:

I got you!

The correct answer is B Fitteen is less than r

To translate that into a numerical inaquiltiy, that is 15<r but the answer to the question is B.

Hope this helps!

Brainliest would be nice!

6 0

3 years ago

Read 2 more answers

A poll shows that 50% of students play sports

Firlakuza [10]

Answer:

The chance of getting a sample proportion of 70% or greater is 0.026.

Step-by-step explanation:

We are given that a poll shows that 50% of students play sports .

A random sample of 20 students showed that 70% of them play sports.

Let $\hat p$ = sample proportion of students who play sports

The z-score probability distribution for the sample proportion is given by;

Z = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of students who play sports = 70%

p = population proportion of students who play sports = 50%

n = sample of students = 20

Now, the chance of getting a sample proportion of 70% or greater is given by = P( $\hat p$ $\geq$ 70%)

P( $\hat p$ $\geq$ 70%) = P( $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ $\geq$ $\frac{0.70-0.50}{\sqrt{\frac{0.70(1-0.70)}{20} } }$ ) = P(Z $\geq$ 1.95) = 1 - P(Z < 1.95)

= 1 - 0.97441 = 0.026

The above probability is calculated by looking at the value of x = 1.95 in the z-table which has an area of 0.97441.

Hence, the chance of getting a sample proportion of 70% or greater is 0.026.

8 0

3 years ago