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MrRissso [65]
3 years ago
13

What is the largest multiple of 9 which is smaller than -70?

Mathematics
2 answers:
sergey [27]3 years ago
6 0

Answer: The number is -72

Step-by-step explanation:

We want the largest multiple of 9 (this is a number equal to 9*r, where r is a real number) that is smaller than -70

So we want the first multiple of 9 that is smaller than -70.

We have that 9*8 = 72

so we will also have that 9*-8 = -72

now, -72 is smaller than - 70

-72 is a multiple of 9.

-72 is the first multiple of 9 smaller than -70 (the next is 9¨-9 = -81 ) so we have that -72 is the largest multiple of 9 that is also smaller than -70.

zysi [14]3 years ago
5 0

Answer:

Step-by-step explanation:

Let's say the number "n" were the largest multiple of 9. But then:  

Consider n + 9. n is itself a multiple of 9, so n = 9k, so n + 9 = 9(k + 1), so n + 9 is also a multiple of 9, and n + 9 is larger than n.  

So there can't be a largest multiple of 9 (or any number).

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pentagon [3]

The results of the composite functions are:

  • (f \times g)(x) = 6x^2-9x
  • f(g(x)) = 6x - 3
  • g(f(x)) = 6x - 9

<h3>What are composite functions?</h3>

Composite functions are functions that are obtained by combining two or more functions together

Assume that:

  • f(x) = 2x - 3
  • g(x) = 3x

Then the computation of the composite functions are as follows:

<h3>Function (f * g)(x)</h3>

(f \times g)(x) = f(x) \times g(x)

(f \times g)(x) = (2x-3) \times (3x)

(f \times g)(x) = 6x^2-9x

<h3>Function f(g(x))</h3>

We have: f(x) = 2x - 3

This gives

f(g(x)) = 2g(x) - 3

So, we have:

f(g(x)) = 2(3x) - 3

f(g(x)) = 6x - 3

<h3>Function g(f(x))</h3>

We have: g(x) = 3x

This gives

g(f(x)) = 3f(x)

So, we have:

g(f(x)) = 3(2x - 3)

g(f(x)) = 6x - 9

Read more about composite functions at:

brainly.com/question/10687170

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2 years ago
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