Question

Given that cos (x) = 1/3, find sin (90 - x)

Answer 1

A/c to trigonometric relations, sin(90 - x) = cos(x),
that means sin(90 - x) = cos(x) = 1/3.

Answer 2

Answer:

$\sin(90^{\circ} - x)=\frac{1}{3}$

Step-by-step explanation:

Given: $\cos (x)=\frac{1}{3}$

We have to find the value of $\sin(90^{\circ} - x)$

Since Given $\cos (x)=\frac{1}{3}$

Using trigonometric identity,

$\sin(90^{\circ} - \theta)=\cos\theta$

Thus, for  $\sin(90^{\circ} - x)$ comparing , we have,

$\theta=x$

We get,

$\sin(90^{\circ} - x)=\cos x=\frac{1}{3}$

Thus, $\sin(90^{\circ} - x)=\frac{1}{3}$