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2 years ago

State the independent variable and dependent variable and find the slope.

1 answer:

4 0

Time is your independent variable, and snowfall is your dependent variable.

Slope can be found by calculating ∆y/∆x:
$x = \frac{0.06 - 0.02}{3 - 1} \\ x = \frac{0.04}{2} \\ x = 0.02$

Snowfall will accumulate 0.02 m every hour.

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In science class, Priscilla heats water and measures the temperature of the water every 2 minutes\or data are shown in the table

Dima020 [189]

Answer:

37.5 °C

Step-by-step explanation:

The temperature appears to be increasing linearly at the rate of 5 °C in 2 minutes, or 2.5 °C per minute.

1 minute after 4 minutes, when the temperature is 35 °C, we expect it to be 2.5 °C higher, or 37.5 °C.

8 0

2 years ago

The vertices of triangle QRS have coordinates Q(1, −2), R(3, −2), and S(2, −4).

Mamont248 [21]

The vertices of triangle QRS have coordinates Q(1, −2), R(3, −2), and S(2, −4). The coordinates are the coordinates of the vertices of triangle QꞌRꞌSꞌ when triangle QRS is reflected across the x-axis Qꞌ(1, 2), Rꞌ(3, 2), Sꞌ(2, 4). The answer is letter B.

6 0

2 years ago

Solve: x - 1 _____=4 2

Brut [27]

Answer:

5-1 = 4

4-2= 2

5 0

2 years ago

The length of a rectangular garden is 8m greater than twice the width the area of the garden is 280m^2 what is the width of the

yarga [219]

Step-by-step explanation:

Given :-

The length of the garden 8m greater than 2 times the width.

Area of the garden is 280 m²

Let us consider the length as x and width as y.

Sp, we can day length as :-

x = 8 + 2y ---(1)

Now, we know that:-

Area of Rectangle = Length × Breadth

280 = x * y

We can replace the value of x now,

280 = y × ( 8 + 2y)

280 = 8y + 2y²

2y² + 8y - 280 = 0

y² + 4y - 140 = 0

Factorise it.

(y -10)(y + 14)

Cancelling -ve value, we get the width as 10 metres.

Hope it helps :)

5 0

2 years ago

Read 2 more answers

A ball is thrown from a height of 32 meters with an initial downward velocity of 2/ms. The ball's height h (in meters) after t s

Bumek [7]

0=65-10t-5t^2

now what you want to do is multiply a and c

-5(t^2+2t-13)

Now just find the zeros

6 0

2 years ago