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velikii [3]
3 years ago
15

The line plot below shows the lengths of bolts Mr. Slivka found in his drawer. He needs 16 bolts that are longer than 1 inch for

a project he is working on. Does he have enough bolts for his project? A line plot named A. Yes. There are 16 bolts that have lengths greater than 1 inch, which is just enough. B. Yes. There are 18 bolts that have lengths greater than 1 inch, which is more than enough. C. No. There are only 3 bolts with lengths greater than 1 inch, which is not enough. D. No. There are only 12 bolts that have lengths greater than 1 inch, which is not enough

Mathematics
1 answer:
AveGali [126]3 years ago
7 0

Answer:

D No. as there are only 12 bolts longer than 1inch.

Mr. Slivka needs 16 bolts of greater than 1 measure, and there are only 12.

Step-by-step explanation:

We cannot include 1 inch data as this is not over 1 inch like the 1inch 2/8 and 1inch 4/8 etc. the greater measures of over 1 inch count to 12.

We know they are greater as they do not have a negative sign next to the added fraction of 1 2/8 or 1 4/8.

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Answer:

he sum of four consecutive integers is -42.

Step-by-step explanation:

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4 years ago
Illinois license plates used to consist of either three letters followed by three digits or two letters followed by four digits.
DENIUS [597]

Answer:

The probability that a randomly chosen plate contains the number 2222 is 0.000028 approximately.

The probability that a randomly chosen plate contains the sub-string HI is 0.002548  approximately.

Step-by-step explanation:

Consider the provided information.

Illinois license plates used to consist of either three letters followed by three digits or two letters followed by four digits.

Part (A)

Let A is the ways in which plates consist of three letters followed by three digits and B is the ways in which two letters followed by four digits.

Here repetition is allow. The number of alphabets are 26 and the number of distinct digits are 10.

The numbers of ways in which three letters followed by three digits can be chosen is: 26\times 26\times 26 \times 10 \times 10 \times10

26^3\times 10^3=17576000

The numbers of ways in which two letters followed by four digits can be chosen is: 26\times 26\times 10 \times 10 \times 10 \times10

26^2\times 10^4=6760000

Hence, the total number of ways are 17576000 + 6760000 = 24336000

Randomly chosen plate contains the number 2222 that means the first two letter can be any alphabets but the rest of the digit should be 2222.

Thus, the total number of ways that a randomly chosen plate contains the number 2222 number are: 26^2=676

The probability that a randomly chosen plate contains the number 2222 is:

\frac{676}{24336000} \approx 0.000028

Part (B)

The number of ways in which chosen plate contains the sub-string HI:

If three letters followed by three digits plate contains the sub-string HI, then the number of possible ways are:

26\times 1\times10^3+1\times 26\times10^3

If two letters followed by four digits plate contains the sub-string HI, then the number of possible ways are:

1\times 10^4

Thus, the total number of ways that a randomly chosen plate contains the sub-string HI are:

1\times 10^4+26\times 1\times10^3+1\times 26\times10^3

62000

From part (A) we know that the total number of ways to chose a number plate is 24336000.

The probability that a randomly chosen plate contains the sub-string HI is:

\frac{62000}{24336000} \approx 0.002548

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Step-by-step explanation:

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x = -2

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