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Tema [17]
3 years ago
5

The product of (2x-3)(3x+5)

Mathematics
1 answer:
madreJ [45]3 years ago
8 0

Answer:

6x² + x − 15

Explanation:

=(2x + −3)(3x + 5)

=(2x)(3x) + (2x)(5) + (−3)(3x) + (−3)(5)

=6x² + 10x − 9x − 15

=6x² + x − 15

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4 years ago
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Write the statement for given expression a) x+3 b) 8-2x K/2 +1
kiruha [24]

Step-by-step explanation:

Decide which of the following are quadratic equations.

(1) x2 + 5x – 2 = 0

(2) y2 = 5y – 10

(3) y2+

1

y

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(4) x+

1

x

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(5) (m + 2) (m – 5) = 0

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ANSWER:

(1) x2 + 5x – 2 = 0

Only one variable x.

Maximum index = 2

So, it is a quadratic equation.

(2) y2 = 5y – 10

Only one variable y.

Maximum index = 2

So, it is a quadratic equation.

(3) y2+

1

y

=2

⇒y3+1=2y

Only one variable y.

Maximum index = 3

So, it is not a quadratic equation.

(4) x+

1

x

=-2

⇒x2+1=-2x

Only one variable x.

Maximum index = 2

So, it is a quadratic equation.

(5) (m + 2) (m – 5) = 0

⇒m2-3m-10=0

Only one variable m.

Maximum index = 2

So, it is a quadratic equation.

(6) m3 + 3m2 – 2 = 3m3

Only one variable m.

Maximum index = 3

So, it is not a quadratic equation.

5 0
3 years ago
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3 years ago
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Hitman42 [59]

By using <em>algebra</em> properties and <em>trigonometric</em> formulas we find that the <em>trigonometric</em> expression \frac{1}{1 - \sin x} - \frac{1}{1 + \sin x} is equivalent to the <em>trigonometric</em> expression \frac{2\cdot \tan x}{\cos x}.

<h3>How to prove a trigonometric equivalence by algebraic and trigonometric procedures</h3>

In this question we have <em>trigonometric</em> expression whose equivalence to another expression has to be proved by using <em>algebra</em> properties and <em>trigonometric</em> formulas, including the <em>fundamental trigonometric</em> formula, that is, cos² x + sin² x = 1. Now we present in detail all steps to prove the equivalence:

\frac{1}{1 - \sin x} - \frac{1}{1 + \sin x}       Given.

\frac{1 + \sin x - 1 + \sin x}{1 - \sin^{2}x}      Subtraction between fractions with different denominator / (- 1) · a = - a.

\frac{2\cdot \sin x}{\cos^{2}x}      Definitions of addition and subtraction / Fundamental trigonometric formula (cos² x + sin² x = 1)

\frac{2\cdot \tan x}{\cos x}      Definition of tangent / Result

By using <em>algebra</em> properties and <em>trigonometric</em> formulas we conclude that the <em>trigonometric</em> expression \frac{1}{1 - \sin x} - \frac{1}{1 + \sin x} is equal to the <em>trigonometric</em> expression \frac{2\cdot \tan x}{\cos x}. Hence, the former expression is equivalent to the latter one.

To learn more on trigonometric equations: brainly.com/question/10083069

#SPJ1

4 0
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