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3 years ago

15

Kristen has 36 purple beads 12 clear beads and 24 yellow beads she wants to put an equal amount of beads and string to make neck

laces with only one color of bead on each string how many beads can Kristen put on each string

1 answer:

KATRIN_1 [288]3 years ago

5 0

She can put 24 on each string.

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The table shows the estimated number of bees, y, in a hive x days after a pesticide is released near the hive.

Oksana_A [137]

Answer:

<h2>A.</h2>

Step-by-step explanation:

The given table is

Days Bees

0 10,000

10 7,500

20 5,600

30 4,200

40 3,200

50 2,400

Where $x$ represents days and $y$ represents bees.

The exponential function that models this problem must be like

$y=a(1-r)^{x}$ , which represenst an exponential decary, because in this case, the number of bees decays.

We nned to use one points, to find the rate of decay. We know that $a=10,000$ , because it starts with 10,000 bees.

Let's use the points (10, 7500)

$y=a(1-r)^{x}\\7500=10000(1-r)^{10}$

Solving for $r$ , we have

$\frac{7500}{10000}=(1-r)^{10} \\(1-r)^{10} =0.75$

Using logarithms, we have

$ln((1-r)^{10}) =ln(0.75)\\10 \times ln(1-r)=ln(0.75)\\ln(1-r)=\frac{ln(0.75)}{10} \approx -0.03\\e^{ln(1-r)}=e^{-0.03}\\1-r =e^{-0.03}\\r=-e^{-0.03}+1 \approx 1.97$

Replacing all values in the model, we have

$y=10000(1-1.97)^{x}\\y=10000(0.97)^{x}$

Therefore, the right answer is the first choice, that's the best approximation to this situation.

6 0

2 years ago

Read 2 more answers

Any help would be great

navik [9.2K]

I believe the perimeter is 45 feet

3 0

2 years ago

On a map, the distance bewtween the two towns is 2.5 inches, and 1 inch represents 6 mile. What is the actual distance between t

Lilit [14]

Answer: 15

Step-by-step explanation:

Ratio is 1 inch:6 mile

2.5 inches divided by 1 inch equals 2.5 inches

2.5 inches times 6 equals 15

4 0

3 years ago

Read 2 more answers

The length of a rectangle is 4 meters less than twice its width. The are of a rectangle is 70m^2. Find the dimensions of the rec

igomit [66]

Answer:

The length is 7 m

The width is 10 m

Step-by-step explanation:

length = x

width = 2x - 4

length * width = area

It is given that the area is 70 $m^{2}$

From there

x * (2x - 4) = 70

$2x^{2}$ - 4x = 70

$2x^{2}$ - 4x - 70 = 0

$x^{2}$ - 2x - 35 = 0

Now we have a quadratic equation, which is a $x^{2}$ + bx + c = 0, where a $\neq$ 0

In this equation a = 1, b = -2 and c = -35

Discriminant (D) formula is b² - 4ac

D = $-2^{2}$ - 4 * 1 * (-35) = 144 > 0

This discriminant is more than 0, so there are two possible x

Their formulas are $\frac{- b - \sqrt{D} }{2a}$ and $\frac{- b + \sqrt{D} }{2a}$

$x_{1}$ = $\frac{- (-2) - \sqrt{144} }{2}$ = -5 < 0 (the length of the rectangle has to be more than 0, so we don't use this x)

$x_{2}$ = $\frac{- (-2) + \sqrt{144} }{2}$ = 7 > 0 (this one is right)

Calculating the dimensions

length = x = 7 (m)

width = 2x - 4 = 2 * 7 - 4 = 10 (m)

8 0

3 years ago

There are 10 balls in an urn, numbered from 1 to 10. If 5 balls are selected at random and their numbers are added, what is the

Kisachek [45]

Let $B_i$ denote the value on the $i$ -th drawn ball. We want to find the expectation of $S=B_1+B_2+B_3+B_4+B_5$ , which by linearity of expectation is

$E[S]=E\left[\displaystyle\sum_{i=1}^5B_i\right]=\sum_{i=1}^5E[B_i]$

(which is true regardless of whether the $X_i$ are independent!)

At any point, the value on any drawn ball is uniformly distributed between the integers from 1 to 10, so that each value has a 1/10 probability of getting drawn, i.e.

$P(X_i=x)=\begin{cases}\frac1{10}&\text{for }x\in\{1,2,\ldots,10\}\\0&\text{otherwise}\end{cases}$

and so

$E[X_i]=\displaystyle\sum_{i=1}^{10}x\,P(X_i=x)=\frac1{10}\frac{10(10+1)}2=5.5$

Then the expected value of the total is

$E[S]=5(5.5)=\boxed{27.5}$

8 0

2 years ago