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2 years ago

Given that S=n/2(2a+(n-1)d). If a=4,d=3 and n=20 find the value of S

Mathematics

2 answers:

Zolol [24]2 years ago

6 0

Answer:

s=650

Step-by-step explanation:

Sum of 'n' terms formula is given by:-

s=n/2(2a+(n-1)d)

s=20/2[2x4+(20-1)3]

s=20/2(2x4+19x3)

s=20/2(8+57)

s=20/2x65

s=10x65

s=650

Thepotemich [5.8K]2 years ago

3 0

Answer:

s=650

Step-by-step explanation:

s=n/2(2a+(n-1)d)

s=20/2[2x4+(20-1)3]

s=20/2(2x4+19x3)

s=20/2(8+57)

s=20/2x65

s=10x65

s=650

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3 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

Find the missing factor x^2-11x+18=(x-2)( )

tia_tia [17]

I'd use synthetic div. here, with 2 as my divisor:

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2 / 1 -11 18
2 -18
----------------------------
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3 years ago

Given that S=n/2(2a+(n-1)d). If a=4,d=3 and n=20 find the value of S​

Given that S=n/2(2a+(n-1)d). If a=4,d=3 and n=20 find the value of S