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Alenkinab [10]
3 years ago
15

Which is the equation of the function?

Mathematics
2 answers:
lozanna [386]3 years ago
8 0

Answer:

D.) f(x) = |x – 1|

Step-by-step explanation:

777dan777 [17]3 years ago
3 0

Answer:

D, f(x) = |x – 1|

Step-by-step explanation:

yw egen2020

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What’s the area of a circle with a circumference of 6.28
3241004551 [841]

Answer:

A = 3.14

Step-by-step explanation:

Area = π r^2

Circumference = 2π r

  1. A = C^2/4π
  2. 6.28^2/4•π ≈ 3.13841
6 0
3 years ago
Write an expression using all six trigonometric functions such that the value of the expression is 3
nlexa [21]
Take Sin of 5 and subtract Cos 2
Sin 5 Cos -2
5-2=3

5x+3=3

√x=3

2x+5y+(1)z=3
3 0
4 years ago
587×6543÷285{32+65}= ? HELP
Ludmilka [50]

Answer:

1307199.57

Step-by-step explanation:

Follow BEDMAS (brackets first, then exponents, then multiplication and division, then addition and subtraction)

587x6543÷285(32+65)

32+65=97

587 x 6543 ÷ 285 x 97

= 3840741 ÷ 285 x 97

= 13476.2842 x 97

= 1307199.57

5 0
2 years ago
PLS HELP ASAP PLSSS IT DETECTS IF ITS RIGHT OR WRONG HELPPP
timurjin [86]

Answer:

y= 250 - 2x

Step-by-step explanation:

She spends $2 per bottle, which is my it's 2x.

She has a total of 250, and she spends $2 per bottle, so you subtract 2x from 250, which leaves the equation at y = 250 - 2x

3 0
3 years ago
Against the wind a commercial airline in South America flew 504 miles in 3.5 hours. With a tailwind the return trip took 3 hours
Sonbull [250]
Recall your d = rt, distance = rate * time

so, notice, it went 504 against the wind, and the return trip, well, unless the road elongated or shrunk somewheres, the return trip is also 504 miles.

now, if say the plane has a still air speed of "p", and the wind has a speed of "w", when it was going against the wind, it wasn't really going "p" fast, it was going "p - w" fast, because the wind was subtracting speed from it.

now, when it was going with the wind, it wasn't going "p" fast either, it was going faster, at "p + w" fast, because the wind was adding to it. thus

\bf \begin{array}{lccclll}
&\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\
&------&------&------\\
\textit{against the wind}&504&p-w&3.5\\
\textit{with the wind}&504&p+w&3
\end{array}
\\\\\\
\begin{cases}
504=3.5(p-w)\implies \frac{504}{3.5}=p-w\\
\qquad 144=p-w\implies \boxed{w}=p-144\\\\
504=3(p+w)\\
----------\\
\frac{504}{3}=p+w\implies 168=p+w\\
\qquad 168=p+\boxed{p-144}
\end{cases}
\\\\\\
168=2p-144\implies \cfrac{168+144}{2}=p\implies 156=p
5 0
4 years ago
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