108<9•12
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3•3 2•6
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1•2 3•2
The curve is y equals 0 from negative x to negative y near x equals negative 8.
If a curve has Vertical Asymptote i.e the line x=p,it is never touched by the given curve.The curve remains almost parallel to the line x=p, till the end.The two i.e a line and curve will never meet each other.
→ x is almost equal to p but not p.
so in the denominator , it is x=-8,
Vertical Asymptote occurs when we put , denominator of curve=0.
so vertical asymptote of curve is : x= -8
Answer:
W > 0.5L
Perimeter:
2L + 2W < 180
2L + 2(0.5L) < 180
2L + 1L < 180
3L < 180
÷3 ÷3
L < 60
Length should be less than or equal to 60 inches while width should be greater than or equal to 30 inches.
Answer:
5!= 120
13!= 6227020800
12!/6!= 665280
10!/7! 3!= 120
5(4!)= 120
Step-by-step explanation:
Answer: a) Yes, there is enough fance
b) 58.1° and 47.9°
c) The city will not approve, because 1/3 of the area is just 2220.5ft²
Step-by-step explanation:
a) using law of cosines: x is the side we do not know.
x² = 126² + 110² - 2.126.110.cos74°
x² = 20335.3
x = 142.6 ft
So 150 > 142.6, there is enough fance
b) using law of sine:
sin 74/ 142.6 = sinα/126 = sinβ/110
sin 74/ 142.6 = sinα/126
0.006741 = sinα/126
sinα = 0.849
α = sin⁻¹(0.849)
α = 58.1°
sin 74/ 142.6 = sinβ/110
sin 74/ 142.6 = sinβ/110
0.006741 = sinβ/110
sinβ = 0.741
β = sin⁻¹(0.741)
β = 47.9°
Checking: 74+58.1+47.9 = 180° ok
c) Using Heron A² = p(p-a)(p-b)(p-c)
p = a+b+c/2
p=126+110+142.6/2
p=189.3
A² = 189.3(189.3-126)(189.3-110)(189.3-142.6)
A = 6661.5 ft²
1/3 A = 2220.5
So 2300 > 2220.5. The area you want to build is bigger than the area available.
The city will not approve
