Question

Quadrilateral ABCD is inscribed in a circle. m∠A is 64°, m∠B is (6x + 4)°, and m∠C is (9x − 1)°. What is m∠D?

Answer 1

Answer:

m∠D = 97.34°

Step-by-step explanation:

Concept used"

sum of all angles of Quadrilateral is 360 degrees.

If any Quadrilateral is inscribed in circles then sum of opposite angle of that Quadrilateral is 180 degrees

________________________________________________

Given

Quadrilateral ABCD is inscribed in a circle

thus,

pair of opposite angles will be

m∠A and m∠C

m∠B and m∠D

thus,

m∠B + m∠D = 180

Thus,

m∠A + m∠C = 180

64+  (9x - 1) = 180

9x = 180 - 63 + 1 = 118

x = 118/9 = 13.11

thus, value of

m∠B is (6x + 4)°

m∠B = (6*13.11 + 4)°  = 82.66°

m∠B + m∠D = 180

82.66 + m∠D = 180

m∠D = 180 - 82.66 = 97.34°

Thus,

m∠D is 97.34°