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Allushta [10]
3 years ago
7

The probability that Stu buys a sandwich is 0.5.

Mathematics
1 answer:
Marizza181 [45]3 years ago
5 0

Answer:

P(S+B)=0.5*0.6=0.3

Step-by-step explanation:

Use the multiplication rule if the events are independent.

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Need an answer, please need an answer, please​
Troyanec [42]

Answer:

Hopefully it will help you... Thanks

6 0
2 years ago
A toy company intends to ship out its entire stock of 13,257 toy trucks and five times as many toy cars. If each box hold 109 to
Leviafan [203]
There are 730 total boxes. The last box has 108 toys.
7 0
3 years ago
A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot
ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box  is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = (x\times x)

                               =x^2

The volume of the box  is = area of the base × height

                                           =x^2h

Therefore,

x^2h=272

\Rightarrow h=\frac{272}{x^2}

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

=20x^2 cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

=10x^2 cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

=4xh\times 1.5 cents

=6xh cents

Total cost = (20x^2+10x^2+6xh)

                =30x^2+6xh

Let

C=30x^2+6xh

Putting the value of h

C=30x^2+6x\times \frac{272}{x^2}

\Rightarrow C=30x^2+\frac{1632}{x}

Differentiating with respect to x

C'=60x-\frac{1632}{x^2}

Again differentiating with respect to x

C''=60+\frac{3264}{x^3}

Now set C'=0

60x-\frac{1632}{x^2}=0

\Rightarrow 60x=\frac{1632}{x^2}

\Rightarrow x^3=\frac{1632}{60}

\Rightarrow x\approx 3

Now C''|_{x=3}=60+\frac{3264}{3^3}>0

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is =\frac{272}{3^2}

                                          =30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

7 0
3 years ago
Hello i need help solving the following inequality X (X + 3) ⩽ X (2X + 5) thanks
igor_vitrenko [27]

Answer:

-2 ⩽ x

Step-by-step explanation:

x(x + 3) ⩽ x (2x + 5) divide both sides of tge inequality with x

x + 3 ⩽ 2x + 5 subtract x from both sides

3 ⩽ x + 5

-2 ⩽ x

3 0
3 years ago
PLEASE HELP?! IM SO CONFUSED!!
seropon [69]

Answer:

C.

Step-by-step explanation:

-3 7/8 rounds down to -4

4.63 rounds up to 5

-4 x 6 + 5

-24 + 5

-19

her answer (-19.14) also rounds to -19

So yes, it is reasonable and the correct response is C.

8 0
1 year ago
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