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Alexus [3.1K]
3 years ago
15

Use the differential equation given by dy/dx=xy/3, y>0 complete the table of values

Mathematics
1 answer:
melisa1 [442]3 years ago
6 0
The \dfrac{\mathrm dy}{\mathrm dx} row is filled by just plugging in the corresponding values of x and y into the ODE.

For example, when x=-1 and y=1, you have

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{xy}3\implies\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=-1,y=1}=\dfrac{(-1)(1)}3=-\dfrac13

and so on.
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79,81,84,88,100,88,82 what is the median of these numbets
pshichka [43]

84 is the median of the numbers



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Ten ways that a ratio and proportions play a big roll in you every day life
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That's all I can think of
3 0
3 years ago
39.6 x 5.20 show your work traditional method
fgiga [73]

Answer:


We have to multiply

⇒39.6 x 5.20 [ Using traditional method]

Traditional method: used by humans when they learnt counting and when fraction came into existence.Suppose something(Area of a field) is divided into parts and another thing(Amount of water used in irrigating the field) is divided into parts and then we have to multiply these two numbers.


3 0
2 years ago
Decrypt the word DKA if it was encrypted using an alphabetic Caesar shift cipher that starts with shift 5 (mapping A to F), and
pochemuha

Answer:

YET

Step-by-step explanation:

TO DECRYPT DKA USING THE CAESAR SHIFT CIPHER STARTING WITH 5 SHIFTS.

TO DO THIS DECRYPTION, WE'RE GOING TO LOOP THE ALPHABETS.

D = LOOPING THIS LETTER 5 TIMES, WE HAVE C - B - A - Z - Y.

SO, D IS DECRYPTED AS Y

GOING FURTHER, THE ENCRYPTION SHIFTS BY AN ADDITIONAL SPACE. THIS MEANS, IF THE FIRST "Y" WAS ENCRYPTED IN 5 SPACES TO GET D, AND AN ADDITIONAL SPACE WAS ADDED TO THE NEXT ALPHABET, IT BECOMES 6.

K IS THEN DECRYPTED AS

K = J - I - H - G - F - E

K IS DECRPYTED AS E

GOING FURTHER, THE NEXT WAS ENCRYPTED WITH AN ADDITIONAL SPACE EVEN MORE, SO, A IS DECRPYTED AS

A = Z - Y - X - W - V - U - T.

THUS, DKA IS DECRYPTED AS YET

5 0
3 years ago
Find the missing side of this right a triangle?<br> help pls
yaroslaw [1]

Hi, there!

 _____

To find the missing side length of this triangle (which is a <em>right</em> triangle), we'll use Pythagoras' Theorem.

-\!\!\!-\!\!\!-\!\!\!\longrightarrow\boldsymbol{a^2+b^2=c^2}

Here,

\textsc{legs:}\begin{cases} \bold{a}\\\bold{b} \end{cases}

Hypotenuse (the longest side): c

We know that

\bold{a=2 \ and \ b=28}

So, we can substitute our parameters, and solve for c.

\bold{2^2+28^2=c^2} -\!\!\!-\!\!\!-\!\!\!\longrightarrow square 2 and 28

\bold{4+784=c^2} -\!\!\!-\!\!\!-\!\!\!\longrightarrow add the numbers

\bold{788=c^2} -\!\!\!-\!\!\!-\!\!\!\longrightarrow square root both sides

\bold{\sqrt{788}=c}

Hope the answer - and explanation - made sense,

happy studying!!

6 0
2 years ago
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