Answer:
X+20=2 i think this is a little above my head
Answer:
Step-by-step explanation:
First, you need to combine like terms in order to begin simplifying. This is done by subtracting 2x from 6x. Also, add 7 to 23.
6x + 10 - 2x = 7 + 23
4x + 10 = 7 + 23
4x + 10 = 30
Now, you have a two-step equation. Subtract 10 from both sides, and then divide by 4.
4x + 10 = 30
4x = 20
x = 5 is the final answer.
<span>280
I'm assuming that this question is badly formatted and that the actual number of appetizers is 7, the number of entres is 10, and that there's 4 choices of desserts. So let's take each course by itself.
You can choose 1 of 7 appetizers. So we have
n = 7
After that, you chose an entre, so the number of possible meals to this point is
n = 7 * 10 = 70
Finally, you finish off with a dessert, so the number of meals is:
n = 70 * 4 = 280
Therefore the number of possible meals you can have is 280.
Note: If the values of 77, 1010 and 44 aren't errors, but are actually correct, then the number of meals is
n = 77 * 1010 * 44 = 3421880
But I believe that it's highly unlikely that the numbers in this problem are correct. Just imagine the amount of time it would take for someone to read a menu with over a thousand entres in it. And working in that kitchen would be an absolute nightmare.</span>
The answer is option B
hope it helps!!
The think the answer is D.