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3 years ago

What is 212.8 divided by 3.8? Plz Help!!

2 answers:

6 0

Easy.

212.8 divided by 3.8 is equivilant to 56. You would solve this by working a long division equation. Please give brainliest, I really need virtuoso.

kakasveta [241]3 years ago

3 0

212.8 divided by 3.8 equals 56. Hope this helped have a good day!

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Find the area of the semicircle with the diameter of 40cm

tresset_1 [31]

Answer:

628.4 cm²

Step-by-step explanation:

Area of semicircle : (πr^2)/2

(3.152*(20^2)) / 2

(3.142 *400) /2

1256.8 / 2

628.4

7 0

4 years ago

Any good mathematicians out there that would help me understand this concept?

algol [13]

The correct answer is (D) because 3 multiple 1/3, the 3 go with 3 and we get the 1. And 9 multiple 1/3, the 9 go with 3 and we will go 3 multiple 1 and we will get 3.

4 0

3 years ago

The equation y = 17x shows that a boat travels at a speed of 17 km/h. Which ordered pair satisfies the equation y = 17x? A. (0,

aleksklad [387]

A, (0,0) is the answer

6 0

3 years ago

What is 4+5 devices by two

icang [17]

The equation can be written as:

4 + 5 / 2

Remember to follow PEMDAS.

4 + 5 / 2

4 + 2.5

6.5

Best of Luck!

3 0

3 years ago

Read 2 more answers

A random sample of 130 students is chosen from a population of 4,500 students. The mean IQ in the sample is 120, with a standard

barxatty [35]

Answer:

$120-2.614\frac{5}{\sqrt{130}}=118.85$

$120+2.614\frac{5}{\sqrt{130}}=121.15$

Step-by-step explanation:

Information given

$\bar X= 120$ represent the sample mean

$\mu$ population mean (variable of interest)

s=5 represent the sample standard deviation

n=130 represent the sample size

For this case we can't set a margin of error just with a % since they not specify 1.13% respect to something for this case we can omit this value

Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom are given by:

$df=n-1=130-1=129$

The Confidence level is 0.99 or 99%, the significance would be $\alpha=0.01$ and $\alpha/2 =0.005$ , and the critical value would be $t_{\alpha/2}=2.614$

And replacing we got:

$120-2.614\frac{5}{\sqrt{130}}=118.85$

$120+2.614\frac{5}{\sqrt{130}}=121.15$

3 0

3 years ago