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Rasek [7]
2 years ago
11

You grab two jelly beans from a jar at the same time. b you draw a card from a deck, replace it, and draw a second. c you draw a

card and do not replace it. then you draw another. d you study english every night, and then you get an a on the next test.
Mathematics
1 answer:
Charra [1.4K]2 years ago
5 0
How is this a question did you re word it
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Give an example of when you had to prove something, and how you did it!
Marizza181 [45]

Answer:

Just practice ,know different ways of solving it ,gain experince ,be smart and skilled.

Step-by-step explanation:

if you want to prove anuthing then go with the concept accoeding to the nature of the problem and there are almost many ways to prove anything so don't waste your time on way get on to the other ways.

It may not get proved at first time so keep on doing questions and when you have gained experience you know every nature of problems and then you are skilled properly.

8 0
3 years ago
Find the area of figure 1.<br><br> 8 units2<br> 14 units2<br> 10 units2<br> 12 units2
sp2606 [1]

Answer:

10 units ^2

Step-by-step explanation:

Area 1:

A = lw

   = 2 * 5 = 10

3 0
2 years ago
Read 2 more answers
Simplify: 12xy - 6x + 3y -10xy - 5y
Darina [25.2K]

Answer:

2xy - 6x +2y

Step-by-step explanation:

12xy - 10xy = 2xy

5y - 3y = 2y

2xy - 6x + 2y

5 0
2 years ago
Read 2 more answers
20 pointss please help I appreciate it &lt;333
ivanzaharov [21]

Answer:

DE = 7.07 RS = 11.04 not congruent

Step-by-step explanation:

Formula:

d=\sqrt{(x2-x1)^2 + (y2-y1)^2}

D (5,0) E (0,-5)

DE

d=\sqrt{(0-5)^2 + ( -5 - 0)^2}

d=\sqrt{(-5)^2 + (-5)^2}

d=\sqrt{25+25}

d=\sqrt{50}

d= 7.07

R (-5,-5) S (6,-6)

RS

d=\sqrt{(6-(-5))^2 + (-6 - (-5))^2 }

d=\sqrt{11^2 + (-1)^2}

d=\sqrt{121 + 1}

d=\sqrt{122}

d= 11.04

3 0
2 years ago
Please help me<br> This is analytic geometry
Vlada [557]

Answer:

The coordinates of point B are (-3,-3).

Step-by-step explanation:

Let A(x,y) = (6,-6), C(x,y) = (-6,-2) and \overrightarrow{AB} = \frac{3}{4}\cdot \overrightarrow{AC}, then we have the following formula by vectorial definition of a line segment:

\overrightarrow{AB} = \frac{3}{4}\cdot \overrightarrow{AC}

B(x,y) -A(x,y) = \frac{3}{4}\cdot [C(x,y)-A(x,y)]

B(x,y) = \frac{3}{4}\cdot C(x,y) +\frac{1}{4}\cdot A(x,y)

B(x,y) = \frac{3}{4}\cdot (-6,-2)+\frac{1}{4}\cdot (6,-6)

B(x,y) = (-3, -3)

5 0
2 years ago
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