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IRINA_888 [86]
3 years ago
6

Hailey has 9 Spirit wear tops and 4 pairs of jeans. How many ways can she pair a top with a pair of jeans?

Mathematics
1 answer:
Len [333]3 years ago
4 0

Answer:

36 ways.

Step-by-step explanation:

To find the total number of ways Hailey can pair a top and a pair of jeans, we just need to multiply the number of possibilities for each item:

number of possibilities for tops: 9

number of possibilities for jeans: 4

Number of different combinations: 9 * 4 = 36

Hailey has 36 different ways of pairing a top and a pair of jeans.

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Your typical markup for merchandise is 40%. Your cost on an item is $8.00. Calculate the selling price.
ratelena [41]
$11.2 is you answer    
7 0
3 years ago
If x = –3 is the only x-intercept of the graph of a quadratic equation, which statement best describes the discriminant of the e
kompoz [17]
\text{ if } \Delta=0\text{ then there is one x-intercept : }x=-\dfrac{b}{2a}\\\\
\text{ if } \Delta\ \textless \ 0\text{ then there are no x-intercept : } x=\varnothing\\\\
\text{ if } \Delta>0\text{ then there are two x-intercept : }x_1,x_2=\dfrac{-b\pm\sqrt{\Delta}}{2a}\\\\

<u>Answer </u>: <span>The discriminant is 0</span>
5 0
3 years ago
Read 2 more answers
A street vendor earns $20 for each day of work plus $4 for
loris [4]

Answer:

(C)

Step-by-step explanation:

20 for each day=20x

4 for hot dogs sold=4x

20x+4x

(C)

4 0
3 years ago
Determine the value of y for y=5x
Ilia_Sergeevich [38]
You just multiply the x value by 5
-2(5)=-10
-1(5)=-5
0(5)=0
3(5)=15
6(5)=30
9(5)=45
5 0
2 years ago
Read 2 more answers
Some of the students three scores is 231. If the first is 20 points more than the second, and the sum of the first two is 6 more
Aleks [24]

Answer:

The first score is 109

Step-by-step explanation:

I am assuming that in the first sentence of the question, you meant:

Sum of the students three scores is 231...

First, let the scores of the first second and third student be a, b and c respectively. We are told that:

a + b + c = 231 . . . . . . . .(1)         (sum of students three scores is 231)

a = b + 20 . . . . . . . . . . . (2)        (the first is 20 points more than the second)

a + b = 6c . . . . . . . . . . . .(3)        (sum of the first two is 6 more times the third)

required, find a.

substituting the value of (a + b) in equation (3) into equation (1), we will have the following:

since a + b = 6c . . . (3)

a + b + c = 231 . . . . . (1), becomes,

(a + b) + c = 231

(6c)  + c = 231

7c = 231 (divide both sides by 7)

c = 231 ÷ 7 = 33

∴ c = 33

Next, from equation (2), we know that a = b + 20; this can also be written as:

a - 20 = b

∴ b = a - 20 . . . . . . . (4)

Finally, putting the value of b in equation (4) and the value of c calculated above into equation 1, ( a + b + c = 231), we have the following:

a + (a - 20) + 33 = 231

(a + a) - 20 + 33 = 231

2a + 13 = 231

2a = 231 - 13 = 218

a = 218 ÷ 2 = 109

∴ a = 109

we can also calculate for 'b' by substituting for the value of 'a' in equation 4

b = a - 20 = 109 - 20 = 89.

and to test if the values of a, b and c are correct:

a + b + c = 231

109 + 89 + 33 = 231

4 0
3 years ago
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