In 10 to the sixth power, the 10 is the power base or exponent

PLZ HELP PLEASE ./////

Harrizon [31]

Answer:

Step-by-step explanation:

The A

3 0

4 years ago

Please help! 20 points!!!

KonstantinChe [14]

Answer:

SOLUTION STEPS

6

8

5

+−6

3

1

Multiply 6 and 8 to get 48.

8

48+5

−

3

6×3+1

Add 48 and 5 to get 53.

8

53

−

3

6×3+1

Multiply 6 and 3 to get 18.

8

53

−

3

18+1

Add 18 and 1 to get 19.

8

53

−

3

19

Least common multiple of 8 and 3 is 24. Convert

8

53

and

3

19

to fractions with denominator 24.

24

159

−

24

152

Since

24

159

and

24

152

have the same denominator, subtract them by subtracting their numerators.

24

159−152

Subtract 152 from 159 to get 7.

24

7

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

E temperature t of a metal sphere is inversely proportional to the distance from the centre of the sphere (the origin (0, 0, 0))

olasank [31]

(-x, -y, -z) the vector form (x, y, z) to the origin, in the direction of the greatest increase.

<h3>How to calculate temperature?</h3>

The quantity or amount of radiation contained in material or item, as measured by a temperature or sensed by touch and stated on a numerical scale.

The temperature T of a ball bearing is inverse to the length first from the origin, which we consider to be the center of the ball. The temperature at the exact location

(x, y, z) is a point on the sphere, the temperature at this point is given by

$T(x,y,z)= \dfrac{k}{(x^2 +y^2+z^2)^{1/2}}$

Where k is constant, then we have

T(1, 2, 2) = k/3 = 170

k = 510

So

$T(x,y,z)= \dfrac{510}{(x^2 +y^2+z^2)^{1/2}}$

Then we have

$\rm \triangledown T = \left ( -\dfrac{510x}{(x^2 +y^2+z^2)^{1/2}}, -\dfrac{510y}{(x^2 +y^2+z^2)^{1/2}}, \dfrac{510z}{(x^2 +y^2+z^2)^{1/2}} \right )\\\\\\\triangledown T (1, 2, 2) = -\dfrac{510}{27} (1, 2, 2) =-\dfrac{170}{9} (1, 2, 2)$

Then the direction will be from (1, 2, 2) to (4, 3, 5) will be (3, 1, 3)

So u = (3/√19, 1/√19, 3/√19)

Then we get

$\rm \triangledown T \cdot u = \dfrac{-170}{9}(1, 2, 2) \cdot \left (\dfrac{3}{\sqrt{19}}, \dfrac{1}{\sqrt{19}}, \dfrac{3}{\sqrt{19}} \right )\\\\\\\triangledown T \cdot u = - \dfrac{170}{9\sqrt{19}} (3 + 2 + 6)\\\\\\\triangledown T \cdot u = -\dfrac{1870}{9\sqrt{19}}$

The direction of the greatest inverse in the temperature is given by any vector parallel to and having the same direction $\triangledown$ T. (-x, -y, -z) the vector form (x, y, z) to the origin, in the direction of the greatest increase.