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Dmitrij [34]
3 years ago
8

Can someone help solve this system of equations?

Mathematics
1 answer:
gladu [14]3 years ago
6 0
You want to get the x by itself so add 3y to the other side and divide 3y+6 by 1 and you get 3y+6 and divide the 6 by 3 and your answer is 2
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Researchers estimate that 21.5% of men and 17% of women smoke. 70.2/100000 men develop lung cancer and 50.5/100000 women 90% of
marishachu [46]
All the probabilities are given for the three different scenarios in men and women: people who smoke, people who develop lung cancer, and people who develop lung cancer who are also smokers. Then, these are even classified in terms of gender.

But the final question only has to do with men who are smokers that develop lung cancer. So, I think all the other data are only there for the purpose of red herring. The answer is already there, but you just have to find it among the others. First, you ignore all the probabilities involving women because we only want the men. Then, you find the probability of men that have lung cancer being smokers. The answer is 90%.
5 0
4 years ago
Write the vertex form of the equation of the parabola which has a vertex of (0,0) and contains the point (2,-2)
Anettt [7]
\bf \qquad \textit{parabola vertex form}\\\\
\begin{array}{llll}
\boxed{y=a(x-{{ h}})^2+{{ k}}}\\\\
x=a(y-{{ k}})^2+{{ h}}
\end{array} \qquad\qquad  vertex\ ({{ h}},{{ k}})\\\\
-------------------------------\\\\
y=a(x-{{ h}})^2+{{ k}}\qquad 
\begin{cases}
h=0\\
k=0
\end{cases}\implies y=a(x-0)^2+0
\\\\\\
y=ax^2\qquad 
\begin{cases}
x=2\\
y=-2
\end{cases}\implies -2=a2^2

solve for "a", to get the coefficient, and then plug it back in the equation.
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