Which expression could be used to determine the cost of a $50 video game after a 20 percent discount?

2 answers:

6 0

The expression that could be used to determine the cost of a $50 video game after a 20 percent discount is:

$50(0.80)

$50(0.80) = $40 discounted amount

$50 * 20% = 10 discount value
$50 - 10 = $40 discounted amount

Agata [3.3K]3 years ago

6 0

If you would like to know the expression that could be used to determine the cost of a $50 video game after a 20 percent discount, you can do this using the following steps:

$50 - 20% of $50 = $50 - 20% * $50 = $50 - 20/100 * $50 = $50 - 1/5 * $50 = $50 - 0.20 * $50 = $50 * 0.80 = $40

The correct result would be $50(0.80).

You might be interested in

The graph shows the result of a matrix transformation, where the pre-image has dashed lines Which matrix operation is represente

diamong [38]

The matrix operation is the addition subtraction and multiplication involving matrices. The coordinates of the image can be represented as a matrix obtained from the coordinates of the preimage through matrix operations

The best correct option is option D), (the y-coordinate for the point (8, -7) is to be replaced with a 7 to give (7, -7) as follows:

$\left[\begin{array}{rrrr}1&0\\0&-1\end{array}\right] \left[\begin{array}{rrrr}9&7&3&2\\-3&-7&-7&-5\end{array}\right]$

The reason the above matrix value for the matrix operation are correct are as follows:

Known parameters:

From the diagram, we have that the coordinates of the vertices of the preimage are;

(2, -5), (3, -7), (9, -3), and (7, -7)

The coordinates of the vertices of the image are;

(2, 5), (3, 7), (9, 3), and (7, 7)

Required:

The matrix operation for the transformation of the preimage points to the image points

Solution:

The transformation from the coordinates of the vertices of primage to the vertices of image involves the change in the sign from negative to positive, of the y-values of the image, which can be obtained by multiplying by (-1)

Therefore, the required matrix operation is presented as follows:

$\mathbf{\left[\begin{array}{rrrr}1&0\\0&-1\end{array}\right] \left[\begin{array}{rrrr}9&7&3&2\\-3&-7&-7&-5\end{array}\right]} =\left[\begin{array}{rrrr}9&7&3&2\\3&7&7&5\end{array}\right]$