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2 years ago

15

Each set of ordered pairs represent a function. writ a rule that represents the function. can you help? (0,1) (1,3) (2,9) (3,27)

(4,81)

1 answer:

Hoochie [10]2 years ago

3 0

X1-x2/y1-y2 is what you need for ordered pair

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For commission as a realtor, Michelle earns $349 plus 3% of the purchase price for each home she helps buy or sell. If she earne

Papessa [141]

Well, let us solve this step by step.

We know that Michelle earns 349 plus 3% of the Purchase price. Let us call the Purchase price as P, so that:

Earnings, E = 349 + 0.03 P

So if she earns 8,965 (E = 8,965) so we can find P:

8,965 = 349 + 0.03 P

0.03 P = 8,616

P = $287,200

8 0

2 years ago

Please look at the picture and answer it.

Savatey [412]

Answer:

y=24

Step-by-step explanation:

4y+7+3y+5=180

7y=168

y=24

6 0

1 year ago

Which property of equality would you use first to solve the equation 6x = 3x

Nadya [2.5K]

Answer:

hghjghgjh

Step-by-step explanation:

6 0

2 years ago

Solve the matrix equation for a, b, c, and d. [1 2] [a b] [6 5][3 4] [c d]= [19 8]

Anit [1.1K]

Answer:

The answer is " $\bold{\left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}7&-2\\ -\frac{1}{2}&\frac{7}{2}\end{array}\right]}$ ".

Step-by-step explanation:

$\bold{\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}6&5\\ 19&8\end{array}\right]}$

Solve the L.H.S part:

$\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}a&b\\c&d\end{array}\right]\\\\\\\left[\begin{array}{cc}a+2c&b+2d\\3a+4c&3b+4d\end{array}\right]$

After calculating the L.H.S part compare the value with R.H.S:

$\left[\begin{array}{cc}a+2c&b+2d\\3a+4c&3b+4d\end{array}\right]= \left[\begin{array}{cc}6&5\\ 19&8\end{array}\right]} \\\\$

$\to a+2c =6....(i)\\\\\to b+2d =5....(ii)\\\\\to 3a+4c =19....(iii)\\\\\to 3b+4d = 8 ....(iv)\\\\$

In equation (i) multiply by 3 and subtract by equation (iii):

$\to 3a+6c=18\\\to 3a+4c=19\\\\\text{subtract}... \\\\\to 2c = -1\\\\\to c= - \frac{1}{2}$

put the value of c in equation (i):

$\to a+ 2 (- \frac{1}{2})=6\\\\\to a- 2 \times \frac{1}{2}=6\\\\\to a- 1=6\\\\\to a =6 +1\\\\\to a = 7\\$

In equation (ii) multiply by 3 then subtract by equation (iv):

$\to 3b+6d=15\\\to 3b+4d=8\\\\\text{subtract...}\\\\\to 2d = 7\\\\\to d= \frac{7}{2}\\$

put the value of d in equation (iv):

$\to 3b+4 (\frac{7}{2})=8\\\\\to 3b+4 \times \frac{7}{2}=8\\\\\to 3b+14=8\\\\\to 3b =8-14\\\\\to 3b = -6\\\\\to b= \frac{-6}{3}\\\\\to b= -2$

The final answer is " $\bold{\left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}7&-2\\ -\frac{1}{2}&\frac{7}{2}\end{array}\right]}$ ".

4 0

3 years ago

A missing fraction on a number line is located exactly halfway between 3/6 and 5/6

Dominik [7]

The missing fraction would be $\frac{4}{6}$ since it is exactly in the halfway between $\frac{3}{6} and \frac{5}{6}$

8 0

2 years ago