The complete question is
A fence must be built to enclose a rectangular area of 5000ft^2. Fencing material costs $1 per foot for the two sides facing north and south and 2$ per foot for the other two sides. Find the cost of the least expensive fence.
Answer:
Total cost will be $400
Step-by-step explanation:
Let x = be other side
y = north and south side
Area = x*y = 5000
Perimeter of the rectangle = 2x + 2y
cost of fencing = 2(1)*5000/x + 2*2x
= 10000/x + 4x
now to get the least we will take the derivative of this
C'(x) = 10000(-1/x^2) + 4 =0
x^2 = 2500
x= 50ft cost = 2*$2*50 = $200
y= 100ft cost = 2*$1*100 = $200
Total cost = $400
X | Y
-2 | 9
-1 | 6
0 | 3
1 | 0
2 | -3
Answer:
-71 + 22n is the equivalent expression.
This is the simplified expression.
Step-by-step explanation:
4(-11 + 4n) -3(-2n + 9)
= -44 + 16n + 6n - 27
= -44 + 22n - 27
= -71 + 22n
Note that any number divided by 0 is undefined.
From the problem,
Since 87 is divided by 0, the answer is undefined
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