Question

For the function

Answer 1

Answer:

x = 1

Step-by-step explanation:

For a quadratic function $f(x)=ax^2+bx+c$, the axis of symmetry is

$x=-\frac{b}{2a}$.

This comes from using part of the Quadratic Formula for finding zeros of the function:

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} = \frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}$

See the -b/(2a) in the first term?  That's the x-coordinate of the vertex (turning point) of the parabolic graph of the function.  The axis of symmetry goes through the vertex.