70 deciliters equals how many liters

Solve for p: 8 = p over 7 please help!!!

frez [133]

Answer: p= 56

8 = p/7

This means to make p by itself, you have to multiple both sides by 7 to cancel out the 7. On the left side, it’d be 8 times 7, which is 56. On the right side, the 7 cancels out and isolates p.

4 0

2 years ago

Calculate the volume of the cylinder, where a = 18 and b = 11. Use 3.14 for pi and round your answer to the nearest tenth.

cupoosta [38]

Answer:

Volume of cylinder $=2797.7$

Step-by-step explanation:

Let $a$ be diameter and $b$ the height of the cylinder

$Then\ radius(r)=\frac{diamater\ (a)}{2}\\\\r=\frac{18}{2}\\\\r=9$

Volume of cylinder $=\pi\times(radius)^2\times(height)$

$=\pi\times(9)^2\times11\ \ \ \ \ \ (\pi=3.14)\\\\=3.14\times9\times9\times11\\\\=2797.74\\\\\approx2797.7$

6 0

3 years ago

Which of the following sjows the correct key features of the graph?

sammy [17]

Answer:

Step-by-step explanation:

y = x^2 - x - 2 is a quadratic function. It's easily factorable: y = (x + 1)(x - 2). Setting this result equal to zero yields the x-intercepts: -1 and 2. This matches the x-intercepts shown on the graph.

The axis of symmetry, x = -b/(2a), derived from the coefficients 1, -1 and -2 of this particular function, is x = 1/2. This x = 1/2 is also the x-coordinate of the vertex. To find the y-coordinate of the vertex, we evaluate y = x^2 - x - 2 at x = 1/2, obtaining:

y = (1/2)^2 - (1/2) - 2, or y = 1/4 - 1/2 - 2, or -2 1/4. This does not quite agree with the y value (-2) shown in the diagram, but is close.

4 0

3 years ago

How can you graph y=5/3x -9

qaws [65]

Answer:

Go to desmos graphing calc

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Test the claim that the mean GPA of night students is larger than 2 at the .025 significance level. The null and alternative hyp

exis [7]

Answer:

$H_0: \, \mu = 2$ .

$H_1:\, \mu > 2$ .

Test statistics: $z \approx 2.582$ .

Critical value: $z_{1 - 0.025} \approx 1.960$ .

Conclusion: reject the null hypothesis.

Step-by-step explanation:

The claim is that the mean $\mu$ is greater than $2$ . This claim should be reflected in the alternative hypothesis:

$H_1:\, \mu > 2$ .

The corresponding null hypothesis would be:

$H_0:\, \mu = 2$ .

In this setup, the null hypothesis $H_0:\, \mu = 2$ suggests that $\mu_0 = 2$ should be the true population mean of GPA.

However, the alternative hypothesis $H_1:\, \mu > 2$ does not agree; this hypothesis suggests that the real population mean should be greater than $\mu_0= 2$ .

One way to test this pair of hypotheses is to sample the population. Assume that the population mean is indeed $\mu_0 = 2$ (i.e., the null hypothesis is true.) How likely would the sample (sample mean $\overline{X} = 2.02$ with sample standard deviation $s = 0.06$ ) be observed in this hypothetical population?

Let $\sigma$ denote the population standard deviation.

Given the large sample size $n = 60$ , the population standard deviation should be approximately equal to that of the sample:

$\sigma \approx s = 0.06$ .

Also because of the large sample size, the central limit theorem implies that $Z= \displaystyle \frac{\overline{X} - \mu_0}{\sigma / \sqrt{n}}$ should be close to a standard normal random variable. Use a $Z$ -test.

Given the observation of $\overline{X} = 2.02$ with sample standard deviation $s = 0.06$ :

$\begin{aligned}z_\text{observed}&= \frac{\overline{X} - \mu_0}{\sigma / \sqrt{n}} \\ &\approx \frac{\overline{X} - \mu_0}{s / \sqrt{n}} = \frac{2.02 - 2}{0.06 / \sqrt{60}} \approx 2.582\end{aligned}$ .

Because the alternative hypothesis suggests that the population mean is greater than $\mu_0 = 2$ , the null hypothesis should be rejected only if the sample mean is too big- not too small. Apply a one-sided right-tailed $z$ -test. The question requested a significant level of $0.025$ . Therefore, the critical value $z_{1 - 0.025}$ should ensure that $P( Z > z_{1 - 0.025}) = 0.025$ .

Look up an inverse $Z$ table. The $z_{1 - 0.025}$ that meets this requirement is $z_{1 - 0.025} \approx 1.960$ .

The $z$ -value observed from the sample is $z_\text{observed}\approx 2.582$ , which is greater than the critical value. In other words, the deviation of the sample from the mean in the null hypothesis is sufficient large, such that the null hypothesis needs to be rejected at this $0.025$ confidence level in favor of the alternative hypothesis.

3 0

3 years ago