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andre [41]
3 years ago
5

What is the solution set to the inequality

Mathematics
2 answers:
creativ13 [48]3 years ago
5 0

(4x - 3)(2x - 1) \geqslant 0 \\ \Leftrightarrow \begin{cases}4x - 3 \geqslant 0 \\ 2x - 1 \geqslant 0\end{cases}\: \vee \:\begin{cases}4x - 3 \leqslant 0 \\2x - 1 \leqslant 0 \end{cases} \\ \Leftrightarrow \begin{cases}x \geqslant  \frac{3}{4}  \\ x  \geqslant  \frac{1}{2} \end{cases}\: \vee \:\begin{cases}x\leqslant  \frac{3}{4}  \\x \leqslant  \frac{1}{2}  \end{cases} \\ \Leftrightarrow x \geqslant  \frac{3}{4} \: \vee \: x \leqslant  \frac{1}{2}  \\ \Rightarrow The\: third\: option

Grace [21]3 years ago
5 0

Answer:

Option C.

Step-by-step explanation:

The given inequality is

\left(4x-3\right)\left(2x-1\right)\geq 0

We know that if ab\geq 0, then either both a and b are positive or both are negative.

Case 1: If both factors are positive.

\left(4x-3\right)\geq 0\Rightarrow x\geq \frac{3}{4}

\left(2x-1\right)\geq 0\Rightarrow x\geq \frac{1}{2}

Using these two equation we get

x\geq \frac{3}{4}

Case 2: If both factors are negative.

\left(4x-3\right)\leq 0\Rightarrow x\leq \frac{3}{4}

\left(2x-1\right)\leq 0\Rightarrow x\leq \frac{1}{2}

Using these two equation we get

x\leq \frac{1}{2}

From case (1) and (2) we get the solution set for the given inequality.

\{x|x\leq \frac{1}{2}\text{ or }x\geq \frac{3}{4}\}

Therefore, the correct option is C.

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