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Ksivusya [100]
3 years ago
13

What is 71,781 divided by 8​

Mathematics
1 answer:
Mashutka [201]3 years ago
7 0
The answer is 8,972.625
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Answer:

m∠1 = 67

Step-by-step explanation:

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A DVD player that regularly sells for $325 is marked down to $225.75. What is the discount rate?
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The answer is 70% off
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Determine whether the study depicts an observational study or an experiment. Thirty university students are divided into two gro
alex41 [277]

Answer:

The provided study is an experiment.

Step-by-step explanation:

Consider the provided information.

Observational study: In this study observer only observe the subjects, and measure variables of interest without allocating treatments to subjects.

For example: you want to examine the  side effect of smoke on lung.

Experiment study:The researchers are applying treatments to experimental units in the research, then the effect of the treatments on the experimental units is observed.

For example: Flipping a coin

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6 0
3 years ago
Scores on a test are normally distributed with a mean of 81.2 and a standard deviation of 3.6. What is the probability of a rand
Misha Larkins [42]

<u>Answer:</u>

The probability of a randomly selected student scoring in between 77.6 and 88.4 is 0.8185.

<u>Solution:</u>

Given, Scores on a test are normally distributed with a mean of 81.2  

And a standard deviation of 3.6.  

We have to find What is the probability of a randomly selected student scoring between 77.6 and 88.4?

For that we are going to subtract probability of getting more than 88.4 from probability of getting more than 77.6  

Now probability of getting more than 88.4 = 1 - area of z – score of 88.4

\mathrm{Now}, \mathrm{z}-\mathrm{score}=\frac{88.4-\mathrm{mean}}{\text {standard deviation}}=\frac{88.4-81.2}{3.6}=\frac{7.2}{3.6}=2

So, probability of getting more than 88.4 = 1 – area of z- score(2)

= 1 – 0.9772 [using z table values]

= 0.0228.

Now probability of getting more than 77.6 = 1 - area of z – score of 77.6

\mathrm{Now}, \mathrm{z}-\text { score }=\frac{77.6-\text { mean }}{\text { standard deviation }}=\frac{77.6-81.2}{3.6}=\frac{-3.6}{3.6}=-1

So, probability of getting more than 77.6 = 1 – area of z- score(-1)

= 1 – 0.1587 [Using z table values]

= 0.8413

Now, probability of getting in between 77.6 and 88.4 = 0.8413 – 0.0228 = 0.8185

Hence, the probability of a randomly selected student getting in between 77.6 and 88.4 is 0.8185.

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3 years ago
Tom is trying to write 2 3/47 as a decimal
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It's about 2.064 if you make the number an improper fraction then divide
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