Question
The hypotenuse of an isosceles right triangle is 11 centimeters longer than either of its legs. find the exact length of each side.
Answer:
![Hypotenuse:37.56](https://tex.z-dn.net/?f=Hypotenuse%3A37.56)
![Other\ Legs: 26.56](https://tex.z-dn.net/?f=Other%5C%20Legs%3A%2026.56)
Step-by-step explanation:
Let the hypotenuse be y and the other legs be x.
So:
![y = 11 + x](https://tex.z-dn.net/?f=y%20%3D%2011%20%2B%20x)
Required
Determine the exact dimension of the triangle
Using Pythagoras theorem;
![y^2 = x^2 + x^2](https://tex.z-dn.net/?f=y%5E2%20%3D%20x%5E2%20%2B%20x%5E2)
![y^2 = 2x^2](https://tex.z-dn.net/?f=y%5E2%20%3D%202x%5E2)
This gives:
![(11+x)^2 = 2x^2](https://tex.z-dn.net/?f=%2811%2Bx%29%5E2%20%3D%202x%5E2)
Open bracket
![121 + 22x + x^2= 2x^2](https://tex.z-dn.net/?f=121%20%2B%2022x%20%2B%20x%5E2%3D%202x%5E2)
Collect like terms
![2x^2 - x^2 -22x - 121 = 0](https://tex.z-dn.net/?f=2x%5E2%20-%20x%5E2%20-22x%20-%20121%20%3D%200)
![x^2 -22x - 121 = 0](https://tex.z-dn.net/?f=x%5E2%20-22x%20-%20121%20%3D%200)
Using quadratic formula:
![x = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B-b%5C%C2%B1%5Csqrt%7Bb%5E2%20-%204ac%7D%7D%7B2a%7D)
![x = \frac{-(-22)\±\sqrt{(-22)^2 - 4*1*-121}}{2*1}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B-%28-22%29%5C%C2%B1%5Csqrt%7B%28-22%29%5E2%20-%204%2A1%2A-121%7D%7D%7B2%2A1%7D)
![x = \frac{-(-22)\±\sqrt{968}}{2*1}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B-%28-22%29%5C%C2%B1%5Csqrt%7B968%7D%7D%7B2%2A1%7D)
![x = \frac{22\±31.11}{2}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B22%5C%C2%B131.11%7D%7B2%7D)
Split
![x = \frac{22+31.11}{2}\ or\ x = \frac{22-31.11}{2}\\](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B22%2B31.11%7D%7B2%7D%5C%20or%5C%20x%20%3D%20%5Cfrac%7B22-31.11%7D%7B2%7D%5C%5C)
![x = \frac{53.11}{2}\ or\ x = \frac{-9.11}{2}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B53.11%7D%7B2%7D%5C%20or%5C%20x%20%3D%20%5Cfrac%7B-9.11%7D%7B2%7D)
x can not be negative.
So:
![x = \frac{53.11}{2}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B53.11%7D%7B2%7D)
![x = 26.56](https://tex.z-dn.net/?f=x%20%3D%2026.56)
Recall that:
![y = 11 + x](https://tex.z-dn.net/?f=y%20%3D%2011%20%2B%20x)
![y = 11 + 26.56](https://tex.z-dn.net/?f=y%20%3D%2011%20%2B%2026.56)
![y = 37.56](https://tex.z-dn.net/?f=y%20%3D%2037.56)
Hence, the dimensions are:
![Hypotenuse:37.56](https://tex.z-dn.net/?f=Hypotenuse%3A37.56)
![Other\ Legs: 26.56](https://tex.z-dn.net/?f=Other%5C%20Legs%3A%2026.56)
39 because 6/3= 2 and 78/39 also = 2
The net diagram could be a cube because a cube has 6 identical sides.
Answer:
something is incorrect in your question.
Step-by-step explanation:
The sum of all three angles in any triangle is only 180°.
I think it’s always because the absolute value is always positive.