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Harman [31]
2 years ago
12

A circle is drawn within a square as shown.

Mathematics
1 answer:
Vinil7 [7]2 years ago
7 0
<h3>Area of shaded region is 21.5 square centimeter</h3>

<em><u>Solution:</u></em>

The area of the shaded region is equal to the area of the square minus the area of the circle

<em><u> Find the area of the square</u></em>

Area\ of\ square = a^2

Where, "a" is the length of each side

From given figure in question,

a = 10 cm

Area\ of\ square = 10^2\\\\Area\ of\ square = 100\ cm^2

<em><u>Find the area of circle </u></em>

The area of the circle is given as:

Area\ of\ circle = \pi r^2

Where, "r" is the radius of circle

Diameter = 10 cm

r = \frac{diameter}{2}\\\\r = \frac{10}{2}\\\\r = 5

Thus,

Area\ of\ circle = 3.14 \times 5^2\\\\Area\ of\ circle = 3.14 \times 25\\\\Area\ of\ circle = 78.5\ cm^2

<em><u>Find the area of the shaded region</u></em>

Area of shaded Region = Area of Square - Area of Circle

Area of shaded Region = 100 - 78.5 = 21.5

Thus area of shaded region is 21.5 square centimeter

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Degree 3 polynomial with zeros 4, 6, and -2.
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Answer:

Step-by-step explanation:

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an Degree 3 polynomial with zeros 4, 6, and -2 is :

f(x) = (x-4)(x-6)(x+2)

all polynomial are : a (x-4)(x-6)(x+2)      a ≠ 0

4 0
3 years ago
two mountain bikers leave from the same parking lot and head in opposite directions on two different trails. the first rider goe
sveta [45]

Applying the required <em>rule </em>or <em>theorem</em>, it can be concluded that the second biker is <u>farther</u> from the <em>parking lot</em>. The distance of the bikers to the <em>parking lot</em> are:

i. First biker = 17.0 km

ii. Second biker = 20.22 km

The <u>path</u> of travel of both bikers would form a triangle. Applying the <u>Pythagoras</u> theorem to the path of the <em>first</em> biker would give his <u>distance</u> from the starting point. While applying the <u>cosine</u> rule to the path of <em>second</em> rider would gives his <u>distance</u> to the starting point.

Thus,

a. <u>To determine the distance of the first biker from the parking lot.</u>

Let the required <em>distance </em>be represented by x. Applying the Pythagoras theorem, we have:

hyp^{2} = adj 1^{2} + adj 2^{2}

x^{2} = 8^{2} + 15^{2}

   = 64 + 225

   = 289

x = \sqrt{289}

  = 17

x = 17 km

Thus, the <u>first</u> biker is 17.0 km from the <em>starting</em> point.

b. <u>To determine the distance of the second biker from the parking lot.</u>

Let the required <em>distance</em> be represented by x. So that applying the cosine rule, we have:

c^{2} = a^{2} + b^{2} - 2ab Cos θ

x^{2} = 8^{2} + 15^{2} - 2(15*8) Cos (180 - 20)

    = 64 + 225 - 240 Cos 160

    = 289 - 240 * -0.5

x^{2} = 289 + 120

   = 409

x = \sqrt{409}

 = 20.2237

x = 20.22 km

Thus, the <u>second</u> biker is 20.22 km from the <em>starting</em> point.

Therefore, the second biker is <u>farther</u> from the <em>parking lot</em>.

A sketch of the path of travel for the two bikers is attached for more clarifications.

Visit: brainly.com/question/22699651

7 0
2 years ago
...................... can yall answer this real quick pleaseee
KIM [24]

Answer:

5.7

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
A chemist is using 351 millimeters of a solution of acid and water. If 18.2% of the solution is acid, how many milliliters of ac
Zolol [24]

Answer:

The % of of acid in solution  = 63.88 ml

Step-by-step explanation:

The solution of acid and water = 351 milliliters

The % of of acid in solution  = 18.2% of 351 ml

Or, The % of of acid in solution  = \frac{18.2}{100} × 351 ml

Or, The % of of acid in solution  = 63.882 ml

Hence ,The % of of acid in solution  = 63.88 ml  Answer

3 0
3 years ago
I need help with this question
mariarad [96]

Answer:

133

Step-by-step explanation:

Answer is 133

6 0
3 years ago
Read 2 more answers
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