Answer:
1. Consistent equations
x + y = 3
x + 2·y = 5
2. Dependent equations
3·x + 2·y = 6
6·x + 4·y = 12
3. Equivalent equations
9·x - 12·y = 6
3·x - 4·y = 2
4. Inconsistent equations
x + 2 = 4 and x + 2 = 6
5. Independent equations
y = -8·x + 4
8·x + 4·y = 0
6. No solution
4 = 2
7. One solution
3·x + 5 = 11
x = 2
Step-by-step explanation:
1. Consistent equations
A consistent equation is one that has a solution, that is there exist a complete set of solution of the unknown values that resolves all the equations in the system.
x + y = 3
x + 2·y = 5
2. Dependent equations
A dependent system of equations consist of the equation of a line presented in two alternate forms, leading to the existence of an infinite number of solutions.
3·x + 2·y = 6
6·x + 4·y = 12
3. Equivalent equations
These are equations with the same roots or solution
e.g. 9·x - 12·y = 6
3·x - 4·y = 2
4. Inconsistent equations
Inconsistent equations are equations that are not solvable based on the provided set of values in the equations
e.g. x + 2 = 4 and x + 2 = 6
5. Independent equations
An independent equation is an equation within a system of equation, that is not derivable based on the other equations
y = -8·x + 4
8·x + 4·y = 0
6. No solution
No solution indicates that the solution is not in existence
Example, 4 = 2
7. One solution
This is an equation that has exactly one solution
Example 3·x + 5 = 11
x = 2
Answer:
0.13
Step-by-step explanation:
cos P = adj/hyp
cos P = 2/16
cos P = 1/8 = 0.125
cos P = 0.13
Answer:
option C is correct answer ..
Step-by-step explanation:
angle A + angle B + angle C = 180° ( by angle sum property of triangle )
3x + 4x-19+ 3x -1 = 180
10x + -20 = 180
10x = 180 +20 = 200
x = 200/10 = 20 °
angle A = 3× 20 = 60 °
angle B = 4× 20 - 1 9 = 61 °
angle C = 3× 20 -1 = 59 °
angle B is greatest so side opposite to it will be greatest in length ....so length of AC is greatest ....
so option C is the correct answer of this question ...
plz mark my answer as brainlist plzzzz vote me also as I have done this question by taking a lot of time Hope it will be helpful for you ....
