Okay for problem 1 heres my explanation
So if you can get 4 bags for 5 cents so I multiplied 5 by 5 to get 25 cents and multiplied 4 by 5 and got 20 for 25 cents but the machine sells you 9 for 25 cents so if you get the m&ms from Jeanie you'll get more for your money if you get it from jeanie
Now problem 2
Now if tom sells 10 cards for 35 cents so theres a 5 cent difference for 2 more cards now 3 cents will be the most likley for the price for one of toms cards and toms price should have been 33 cents so your only being robbed of 2 cents not a big amount but we'll still look at the other guy 12 cards for 40 cents now if we look at how much toms cards will be if you bought 12 is only 39 cents 1 cent less than the other guy so in conclusion if you buy from Tom you get the better buy
Now problem 3
simple mutipily 19x4 and 76 cents the guys at the firework stands charge 85 for four so if you go to the hardware store and buy your fireworks there you get a better deal.
okay so im running out of time so someone else is gonna answer the last problem... sorry m8
Answer:
Both A and B will get rid of the 8y variable in both equations
Answer:
x=5,1
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.
Dividing the parallelogram in half and applying trigonometry is the easiest solution for me.
Answer:
The expected number of graphing calculators that malfunctions within 3 months and need to be replaced is 915,000.
Step-by-step explanation:
Let <em>X</em> represents the number of graphing calculator that starts malfunctioning within 36 months of the purchase and needs to be replaced by a new one.
It is provided that <em>X</em> follows a normal distribution with a mean of 54 months and a standard deviation of 8 months.
Also, using the normal model it was determined that 1.22% of graphing calculator manufactured by Texas Instruments malfunctions and needs replacement.
That is,
P (<em>X</em>) = 0.0122
Texas Instruments has sold 75 million graphing calculators world- wide.
Compute the expected number of graphing calculators that malfunctions within 3 months and need to be replaced as follows:
E (<em>X</em>) = n × P (<em>X</em>)
= 75 × 10⁶ × 0.0122
= 915000
Thus, the expected number of graphing calculators that malfunctions within 3 months and need to be replaced is 915,000.