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jek_recluse [69]
3 years ago
8

3 1/5 less than 1, equal to 1, or greater than 1?

Mathematics
2 answers:
NARA [144]3 years ago
6 0

Answer:

Greater Than 1

Step-by-step explanation:

blagie [28]3 years ago
5 0

Answer:greater than 1

Step-by-step explanation:

It’s bigger than 1

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Hey, tell me if this is the kind of stuff your math teacher gives you ( I got this too)
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Answer:

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3 years ago
I need help with this problem ASAP!
Karo-lina-s [1.5K]

Form a right angle triangle joining both given points to the origin, we get:

Perpendicular = 2 ( distance is always positive)

Base = 4 ( same logic)

Applying Pythagorus theorem

Hypotenuse = root of ( perpendicular squared + base squared)

Hypotenuse = root of 20 = 2 * root 5

Using x instead of theta

Sin x = perpendicular/hypotenuse

Cos x = base/hypotenuse

Sin x = -1/ root 5

Cos x = -2/ root 5

High probability of this answer being wrong.

Double check recommended.

4 0
3 years ago
A bucket contains 5 green tennis balls, two yellow tennis balls, 6 red tennis balls, and 8 blue tennis balls. Tony removes 4 ten
lbvjy [14]
Total amount of tennis balls:

5 green tennis balls + 2 yellow tennis balls + 6 red tennis balls + 8 blue tennis balls = 21 tennis balls.

The problem says that Tony removes 4 tennis balls without replacement, so:

Let's call Event A= yellow, green, blue, green
P(A) = (2/21)(5/20)(8/19)(4/18)
P(A) = 2.23x10^-3
P(A) = 0.00223
P(A) = 0.223%
5 0
3 years ago
Read 2 more answers
Find the exact volume of a waffle ice cream cone with 15-in. Diameter and a height of 23 inches
Andrew [12]
Radius = 15/2 = 7.5
Volume of cone: pi(r)^2*h/2
= pi(7.5)^2*23/2
pi(56.25) * 23/2
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4 0
3 years ago
(5x^5) - (80x^3)<br> factoring
elena55 [62]

Answer:

Factoring the term (5x^5) - (80x^3) we get \mathbf{5x^3(x-4)(x+4)}

Step-by-step explanation:

We need to factor the term (5x^5) - (80x^3)

First we can see that 5x^3 is common in both terms

So, taking 5x^3 common:

(5x^5) - (80x^3)\\=5x^3(x^2-16)

We can write x^2-16 as (x)^2-(4)^2

=5x^3((x)^2-(4)^2)

Now we can solve (x)^2-(4)^2 using the formula: a^2-b^2=(a+b)(a-b)

We can write:

=5x^3((x)^2-(4)^2)\\=5x^3(x-4)(x+4)

So, factoring the term (5x^5) - (80x^3) we get \mathbf{5x^3(x-4)(x+4)}

4 0
3 years ago
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