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Elena L [17]
3 years ago
7

How is place value used to read decimals

Mathematics
1 answer:
Bas_tet [7]3 years ago
6 0
It is used by telling which number is in what value
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claire makes bracelets using blue and red beads. each bracelet has 20 red beads and 5 blue beads. write an ordered pair to repre
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B=blue bead
R=red bead

1 bracelet = rrrrbrrrrbrrrrbrrrrbrrrrb
Then that would be repeated for the rest of the bracelets
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Help me out don’t really get this stuff that much
ioda

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Step-by-step explanation:

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I am unsure about how to solve this problem. May I have some advice how to solve it?
dolphi86 [110]

Answer:

sin ^2 x+ cos ^2 x = 1

Step-by-step explanation:

sin^2 x - cos ^2 x sin ^2 x = sin ^4 x

Factor sin^2 x

sin ^2 x ( 1- cos ^2 x ) = sin ^4 x

Using the identity   sin ^2 x+ cos ^2 x = 1  written as 1 -cos ^2 x = sin ^2 x

sin ^2 x ( sin^2 x ) = sin ^4 x

sin ^4 x = sin ^4 x  

 

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4 years ago
Caleb scored 60 on his first math test. He studied diligently for the next test and earned a score of 90. What is his percent of
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7 0
4 years ago
Determine if diverges, converges, or converges conditionally.
TEA [102]

The given series is conditionally convergent. This can be obtained by using alternating series test first and then comparing the series to the harmonic series.

<h3>Determine if diverges, converges, or converges conditionally:</h3>

Initially we need to know what Absolute convergence and Conditional convergence,

If \sum|a_{n} | → converges, and \sum a_{n} → converges, then the series is Absolute convergence

If \sum|a_{n} | → diverges, and \sum a_{n} → converges, then the series is Conditional convergence

First use alternating series test,

\lim_{k \to \infty} \frac{k^{5} +1}{k^{6}+11 } = \lim_{n \to \infty} \frac{5}{6k} = 0,

The series is a positive, decreasing sequence that converges to 0.

Next by comparing the series to harmonic series,

\sum^{\infty} _{k=2}|(-1)^{k+1} \frac{k^{5} +1}{k^{6}+11 }|=\sum^{\infty} _{k=2}\frac{k^{5} +1}{k^{6}+11 } ≈  \sum^{\infty} _{k=2}\frac{1}{k} = 0

This implies that the series is divergent by comparison to the harmonic series.

First we got that the series is converging and then we got the series is divergent. Therefore the series is conditionally convergent.

\sum|a_{n} | → diverges, and \sum a_{n} → converges, then the series is Conditional convergence.

Hence the given series is conditionally convergent.

Learn more about conditionally convergent here:

brainly.com/question/1580821

#SPJ1

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2 years ago
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